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stealth61 [152]
3 years ago
12

Nt divided by n plus t, for n equals 15 and t equals 7

Mathematics
1 answer:
ohaa [14]3 years ago
7 0

nt / (n+t)

substitute n=15 and t=7

(15*7)/(15+7)

105/22

22 goes into 105 4 times with 17 left over

4 17 /22

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(10 POINTS!) How would you write 1 cubic foot as a cubic measure?
Tema [17]

Answer:

1 cubic ft can also be 1728in3, or 0.03704 yd3

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3 years ago
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Flura [38]

Answer:

D) cot(C) = 1/2.

Step-by-step explanation:

We can go through each choice and examine is validity.

Choice A)

We have:

\displaystyle \sec B=\frac{3}{7}

Recall that secant is the ratio of the hypotenuse to the adjacent.

With respect to B, the adjacent is 6 and the hypotenuse is 7.

Therefore, sec(B) should be 7/6 instead.

A is incorrect.

Choice B)

We have:

\displaystyle \cot B=\frac{3}{2}

Cotangent is the ratio of the adjacent side to the opposite.

With respect to B, the adjacent side is 6 and the opposite side is 3.

Therefore, cot(B) = 6/3 = 2.

B is incorrect.

Choice C)

C is incorrect for the reasons listed in A.

Choice D)

We have:

\displaystyle \cot C=\frac{1}{2}

Again, cotangent is the ratio of the adjacent side to the opposite.

With respect to C, the adjacent side is 3 and the opposite side is 6.

So, cot(C) = 3/6 = 1/2.

Therefore, D is the correct choice!

8 0
3 years ago
Jerry played with 333 friends today, all at different times. He played with Tommy for 1\dfrac{7}{8}1 8 7 ​ 1, start fraction, 7,
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Answer:

8 1/8 hours

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Jerry played with 3 friends today, all at different times.

Tommy = 1 7/8 hours

Nathan = 1 3/4 hours

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Number of hours Jerry play with his 3 friends today = 1 7/8 + 1 3/4 + 3 3/2

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5 0
3 years ago
A carpenter wants to expand a square room. The new room will have one side 4 feet longer and the adjacent side 6 feet longer tha
gogolik [260]

Answer:

  Dimensions of original room = 12 x 12 feet.

Explanation:

 Let the size of old square room be a x a.

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              10a = 120

                  a = 12 feet.

 Dimensions of original room = 12 x 12 feet.

 

8 0
3 years ago
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