All categories

2 years ago

In the diagram below, O is circumscribed about quadrilateral ABCD. what is the value of x?

Mathematics

2 answers:

cestrela7 [59]2 years ago

7 0

Answer:

104

Step-by-step explanation:

cuz it iz

netineya [11]2 years ago

6 0

Answer:

(D) $x=104^{\circ}$

Step-by-step explanation:

Given: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

To find: the value of x.

Solution: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

We know that the sum of opposite angles of the cyclic quadrilateral is 180°, therefore

${\angle}ABC+{\angle}ADC=180^{\circ}$

Substituting the given values, we have

$91^{\circ}+x-15^{\circ}=180^{\circ}$

$x+76^{\circ}=180^{\circ}$

$x=104^{\circ}$

thus, the value of x is $104^{\circ}$ .

Hence, option D is correct.

You might be interested in

Let f(x) = 2x - 7 and g(x) = -6x - 3. Find f(x) + g(x) and state its domain.

Klio2033 [76]

2x-7+-6x-3 2x+-6x=-4x
-4x-10=0
-5/2 is the answer

7 0

3 years ago

How long does it take to reach 1 million if you keep doubling a number everyday?

Darya [45]

28 days or 672 hours

8 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

True or False: (x + 3)2 = x2 + 9

malfutka [58]

Answer:

false

Step-by-step explanation:

3 0

3 years ago

The area of each square is 25 square unit what's the perimeter

Lerok [7]

Since the area of a square is side squared, you can find the length of each side by finding the square root of the area, which is 5. Since there are four sides in a circle, just multiple 5 by 4 and your answer is 20 units.

7 0

2 years ago

In the diagram below, O is circumscribed about quadrilateral ABCD. what is the value of x?​

In the diagram below, O is circumscribed about quadrilateral ABCD. what is the value of x?