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topjm [15]
3 years ago
15

In the diagram below, O is circumscribed about quadrilateral ABCD. what is the value of x?​

Mathematics
2 answers:
cestrela7 [59]3 years ago
7 0

Answer:

104

Step-by-step explanation:

cuz it iz

netineya [11]3 years ago
6 0

Answer:

(D)x=104^{\circ}

Step-by-step explanation:

Given: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

To find: the value of x.

Solution: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

We know that the sum of opposite angles of the cyclic quadrilateral is 180°, therefore

{\angle}ABC+{\angle}ADC=180^{\circ}

Substituting the given values, we have

91^{\circ}+x-15^{\circ}=180^{\circ}

x+76^{\circ}=180^{\circ}

x=104^{\circ}

thus, the value of x is 104^{\circ}.

Hence, option D is correct.

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