Question

In the diagram below, O is circumscribed about quadrilateral ABCD. what is the value of x?​

Answer 1

Answer:

104

Step-by-step explanation:

cuz it iz

Answer 2

Answer:

(D)$x=104^{\circ}$

Step-by-step explanation:

Given: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

To find: the value of x.

Solution: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

We know that the sum of opposite angles of the cyclic quadrilateral is 180°, therefore

${\angle}ABC+{\angle}ADC=180^{\circ}$

Substituting the given values, we have

$91^{\circ}+x-15^{\circ}=180^{\circ}$

$x+76^{\circ}=180^{\circ}$

$x=104^{\circ}$

thus, the value of x is $104^{\circ}$.

Hence, option D is correct.