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Tanzania [10]
3 years ago
12

Law of cosines: a2 = b2 + c2 – 2bccos(A) Which equation correctly applies the law of cosines to solve for an unknown angle measu

re?
72 = 82 + 112 – 2(8)(11)cos(N)
82 = 72 + 112 – 2(7)(11)cos(M)
72 = 82 + 112 – 2(8)(11)cos(P)
82 = 72 + 112 – 2(7)(11)cos(P)

Mathematics
2 answers:
Cloud [144]3 years ago
8 0
The law of cosines is used for calculating one side of the triangle if the angle opposite to that side is given as well as the other sides. For this problem, we are given angle B. Therefore, the correct answer among the choices given is option 1 where a is equal to 5 and c is equal to 3.
guajiro [1.7K]3 years ago
8 0

Answer:

d on edge

Step-by-step explanation:

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What is the slope of the function?<br> –10<br> - 5<br> 5<br> 10
Eduardwww [97]

Answer:

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what is the function?

a slope going up means it is positive and a slope going down means it is negative

7 0
2 years ago
Please help me with this
Arturiano [62]

Answer: d

Step-by-step explanation:

7 0
3 years ago
A block is 12 g and volume is 6 what is the density
WITCHER [35]

Answer: c.)2 g/ml is the correct answer.

8 0
3 years ago
What is the y-coordinate of the solution to this system of equations?<br> 5x-8y=1<br> 3x+6y=-21
Vanyuwa [196]

5x-8y=1...(1)
3x+6y=-21...(2)

(1)*3:
15x-24y=3...(3)

(2)*5:
15x+30y=-105...(2)

(3)-(2):
15x-24y-(15x+30y)=3-(-105)
15x-24y-15x-30y=108
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6 0
3 years ago
Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.
puteri [66]

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

A=\dfrac{a+b}{2}h

Where, a,b are parallel sides and h is the vertical distance between the parallel sides.

Putting a=28.7, b=22.3,h=16 in the above formula, we get

A=\dfrac{28.7+22.3}{2}\times(16)

A=\dfrac{51}{2}\times 16

A=51\times 8

A=408

Therefore, the area of the trapezium is 408 square cm.

4 0
3 years ago
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