Answer:
Possible ways to paint the house is 108
Step-by-step explanation:
Total number of houses to be painted=4
Total number of colours to b used(red,blue,green and yellow)=4
Number of ways to paint the first house=4
Number of ways to paint the second house=3
Number of ways to paint the third house=3
Number of ways to paint the fourth house=3
Total number of ways to paint the 4 houses=4×3^3=108 ways.
It's the arithmetic sequence not geometric sequence.
First I find the individual widget weight
81 - 73 = 2x
8 = 2x
x = 4
Then I find how many widgets were left
73 - 1 = 4y
72 = 4y
18 = y
Y is the amount of widgets left, therefore the amount left is 18
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