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andrezito [222]
3 years ago
10

A race car is equipped with a computer that records the reading on its speedometer every second during a race. if you graph this

data, what will be the best choice for the dependent variable?
a. time
b. position
c. average velocity
d. instantaneous velocity
Mathematics
2 answers:
marin [14]3 years ago
6 0
I think that the instantaneous velocity would depend on the time so I think It would be D
Eva8 [605]3 years ago
3 0
D.) Dependent variable is "<span>instantaneous velocity" as it gives information of velocity at every second

Hope this helps!</span>
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Tara walks 2 miles in 30 minutes At this rate,how far can Tara walk in 45 minutes?​
nevsk [136]

Answer:

Step-by-step explanation:

In 30 minutes she can walk 2 miles. We'll put that as a ratio. 30:2. Now to figure out how much she walks in 45 minutes, we set variable to x and make it stand for how much she walks. We have 30:2 = 45:x We cross multiply to get 30x=90, x=3. Tara can walk 3 miles in 45 minutes.

5 0
3 years ago
Solve the System and write the solution as an ordered pair. <br><br> 3x+3y=6 <br> 5x-6y=15
Ugo [173]

\\ \sf\longmapsto 3x+3y=6\dots(1)

\\ \sf\longmapsto 5x-6y=15\dots(2)

Multiply eq(1) by 2 and eq(2) by 1

\\ \sf\longmapsto 6x+6y=12

\\ \sf\longmapsto 5x-6y=15

  • Add

\\ \sf\longmapsto 11x=27

\\ \sf\longmapsto x=\dfrac{27}{11}

Now

Put in eq(1)

\\ \sf\longmapsto 3\dfrac{27}{11}+3y=6

\\ \sf\longmapsto \dfrac{81}{11}+3y=6

\\ \sf\longmapsto 3y=6-\dfrac{81}{11}

\\ \sf\longmapsto 3y=\dfrac{66-81}{11}

\\ \sf\longmapsto 3y=\dfrac{15}{11}

\\ \sf\longmapsto y=\dfrac{15}{33}

4 0
3 years ago
Read 2 more answers
Please help find the value of t?
Gwar [14]

Step-by-step explanation:

volume=8448m²

volume=l×b×h

=11m×8m×t

=88m²×t

therefore, 88m²×t=8448m²

t= 8448/88

= 96

Check:-

volume= l×b×h

=11m×8m×96

=8448m³

Our answer is correct

4 0
3 years ago
What is a risk management plan?
Ira Lisetskai [31]
a document that a project manager prepares to foresee risks, estimate impacts, and define responses to issues. It also contains a risk assessment matrix.
6 0
3 years ago
Read 2 more answers
graph the parabola y equals negative x squared + 3 to graph a parabola plot the vertex and four additional points two on each si
Nataliya [291]

You don't have the graph icon here, so we'll have to graph this parabola without it.


Your parabola is y = -x^2 + 3., which resembles y = a(x-h)^2 + k. We can tell immediately that this parabola opens down and that the vertex is (0,3).


Plot (0,3). Besides being the vertex, this point is also the max. of the function.


Now calculate four more points. Choose four arbitrary x-values, such as {-2, 1, 4, 5} and find the y value for each one. Plot the resulting four points. Draw a smooth curve thru them, remembering (again) that the vertex is at (0,3) and that the parabola opens down.

6 0
3 years ago
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