Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25
Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)
P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)
P(X=3)=p(3,1) +p(3,2) +p(3,3)
P(X=3)=0.05+0.1+0.25=0.4

Hence P(Y=1|X=3)=0.125
y + (2x -12) = 180 (since they are supplementary angles)
(2x-12) = 96 ( since they are alternate exterior angle)
2x = 96 + 12
2x = 108
x = 108/2
x = 54.
y+( 2x-12)=180
y+(2× 54 -12) = 180
y + (108-12) = 180
y + 96 = 180
y= 180-96
y = 84.
Answer:
thanks:)
Step-by-step explanation:
hehe
C is the answer to that question i think