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3 years ago

What are the laws of exponents

Mathematics

2 answers:

Kitty [74]3 years ago

4 0

Answer:

One rule to remember that everyone forgets is, multiply the base number as many times as what the exponent is. So for example, 3² is not 3 x 2 = 6, it's 3 x 3 = 9. Hope that makes sense! :)

Step-by-step explanation:

mafiozo [28]3 years ago

3 0

The exponent of a number says how many times to use the number in multiplication.

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Factor by grouping 20x^3-12x^2+15x-9

GREYUIT [131]

Factor out common terms in the first two terms, then in the last two terms

4x^2(5x - 3) + 3(5x - 3)

Factor out the common term 5x - 3

= (5x - 3)(4x^2 + 3)

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3 years ago

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8 0

4 years ago

The Average cost of a long distance call in the USA was 31 cents per minute in 1978 and 8 cents in 2008. Find the approximate pe

olya-2409 [2.1K]

Answer:

74%

Step-by-step explanation:

We have been given that the Average cost of a long distance call in the USA was 31 cents per minute in 1978 and 8 cents in 2008.

We will use percent decrease formula to solve our given problem.

$\text{Percent decrease}=\frac{\text{Initial}-\text{Final}}{\text{Initial}}\times 100\%$

$\text{Percent decrease}=\frac{31-8}{31}\times 100\%$

$\text{Percent decrease}=\frac{23}{31}\times 100\%$

$\text{Percent decrease}=0.741935483\times 100\%$

$\text{Percent decrease}=74.1935483\%$

$\text{Percent decrease}\approx 74\%$

Therefore, there is an approximate 74% decrease in cost per minute for the long distance call from 1978 to 2008.

4 0

3 years ago

45 points If you help me with these please ?????ASAP

Nata [24]

Answer:

Step-by-step explanation:

the first graph has points (-1, -1) and (2, -2)

slope m = (y2-y1) / (x2-x1) = (-1+2)/ (-1-2) = 1/-3 = -1/3

the second graph has points (0, -3) and (2, 0)

slope m = (y2-y1) / (x2-x1) = (-3-0)/ (0-2) = -3/-2 = 3/2

for the table

x. y

-3. 4

0. 1

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5 0

3 years ago

Solve this equation for x. Round your answer to the nearest hundredth. 0.77 = log x

Alekssandra [29.7K]

Answer:

x ≈ 5.89

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Algebra II

Exponential to Logarithmic: $\displaystyle b^m=x \rightarrow log_bx=m$

Step-by-step explanation:

Step 1: Define

Identify

0.77 = log(x)

Step 2: Solve for x

[Equality Property] Raise both sides to the 10th power: $\displaysytle 10^{0.77} = 10^{logx}$
Simplify: $\displaysytle x = 10^{0.77}$
Evaluate: $\displaysytle x = 5.88844$

8 0

3 years ago