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elena55 [62]
3 years ago
6

Please help!!! 20 points

Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:

a

Step-by-step explanation:

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Two companies offer jane sales position. Company a pays $3,000 per month plus $250 per car sold.. Company B pays 2,500 per month
Montano1993 [528]

Given :

Two companies offer jane sales position. Company a pays $3,000 per month plus $250 per car sold.. Company B pays 2,500 per month plus $350 per car sold.

To Find :

Which equation could be used to determine the number of cars sold in a month, x, that would result in the same total income from each company.

Solution :

Let, x car are sold for same income.

Mathematical equation of company one :

T_1 =3000+250x

Mathematical equation of company two :

T_2 =2500+350x

For same income :

T_1=T_2\\\\3000 + 250x = 2500 + 350x\\\\100x = 500\\\\x=5

So, for same total income from each company the number of cars sold in a month should be 5.

Hence, this is the required solution.

3 0
3 years ago
The function h(x)=4/3x-1 represents the composite h(x)=f(g(x)).if f(x)=2x-1,what is g(x)
Hunter-Best [27]

Answer:

g( x) = \frac{2}{3}x

Step-by-step explanation:

Given:

Composite Function:

h( x)=f( g( x))

Also,

h( x)=\frac{4}{3}x-1

To find:

g( x )  = ?

Solution:

First of all, let us learn about a composite function.

Composite function f( g( x)) means to write g( x) in place of x in the function f( x).

Let g( x) = y

So, f( g( x)) =  f( y ).

Therefore,

h( x) =f( g( x)) = f( y)

So, f( y) = 2y-1

We have to solve for y in terms of x to find the value of g(x):

\Rightarrow \frac{4}{3}x-1 = 2y-1\\\Rightarrow 2y=\frac{4}{3}x\\\Rightarrow y = \frac{2}{3}x

Hence, the answer is g(  x ) = \frac{2}{3}x.

Checking whether the answer is correct or not:

f( g( x)) = f( \frac{2}{3}x) = 2\times \frac{2}{3}x -1 = \frac{4}{3}x-1

which is h( x).

Hence, our answer g( x ) = \frac{2}{3}x is correct.

6 0
3 years ago
Read 2 more answers
Determine the function which corresponds to the given graph<br> The asymptote is x=3
stepladder [879]
The function has a horizontal asymptote at y = 3.
The function has a vertical asymptote at x = -3.
The function has a  vertical intercept of 1.
The function has a zero of x = -2.

Because the function has a zero at x = -2, and a vertical asymptote at x = -3, therefore
y= \frac{k(x+2)}{x+3}

Write the function in the form
y = y= \frac{k(1+ \frac{2}{x}) }{1+ \frac{3}{x} }

As x → ∞, y → k.
Because a horizontal asymptote exists at y = 3, therefore  k = 3.
A vertical intercept exists at y = 1.
The function is
 y =  \frac{3(x+2)(x+1)}{(x+3)(x+1)}

Answer: y =  \frac{3(x+2)(x+1)}{(x+3)(x+1)}


5 0
3 years ago
What is the following product?
ivanzaharov [21]

Answer:

the trid one becasue

Step-by-step explanation:

To get the correct answer, you can count the total number of shaded tenths and the total number of shaded hundredths and then regroup.

There are 9 shaded tenths and 18 shaded hundredths. Regroup 10 hundredths into 1 tenth to get 10 tenths and 8 hundredths. Then regroup the 10 tenths in one whole, giving you 1 whole and 8 hundredths. The product is 1.08.

Another way to get the answer is to count the total number of shaded hundredths. There are 108 hundredths. Regroup 100 of them as one whole, giving you 1 whole and 8 hundredths.

6 0
3 years ago
In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee
kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that x^{2} =pz

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and  Δ ADB in the attached file , ∠A is common in both triangles

                                                                     and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

\frac{x}{z}= \frac{p}{x}

Cross multiply

x^{2}=pz

Hence proved.


7 0
4 years ago
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