<span>One cubic foot is 12 times higher, wider and thicker. So its 1728 larger.
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A∩B={25, 45, 65}
A∩B=the elements that belong to both set A and set B
1. Similarity ratio: ΔMON : ΔJOK = 4 : 3
2. Theorem to justify similarity: SAS.
.. MO = 4/3 JO
.. ∠O = ∠O
.. NO = 4/3 KO
3. Similarity statement: ΔMON ~ ΔJOK by SAS.
Area = πr²
50 = πr²
r = √50/π
so diameter = 2√50/π
which is = 7.98m to 3sf
2(4z−2) = 44
Simplify both sides of the equation.
Distribute:
(2)(4z)+(2)(−2) = 44
8z + −4 = 44
8z − 4 = 44
Add 4 to both sides.
8z − 4 + 4 = 44 + 4
8z = 48
Divide both sides by 8
8z/8 48/8
z = 6