Help I need this asap I will give the brainiest

Does anyone know the answer to this question??

Step2247 [10]

C and then D because when you go outside and it’s cold then you know it’s cold

6 0

2 years ago

Daisy Hill has saved $5,000 for her first semester of college. She plans to

Katarina [22]

Amount Daisy plans to spend on food is $625

Step-by-step explanation:

Step 1: Given total savings of Daisy = $5000. Find the amount spent by Daisy on her room

Amount spent on room = 3/4 of 5000 = 3/4 × 5000 = $3750

Step 2: Calculate the remaining amount.

Remaining amount = $5000 - $3750 = $1250

Step 3: Calculate the amount Daisy plans to spend on food

Amount to be spend on food = 1/2 of 1250 = 1/2 × 1250 = $625

5 0

3 years ago

Read 2 more answers

An aquarium is leaking water at the rate of three quarts in 4 days.How many quarts are leaked in 1 week?How many days does it ta

Simora [160]

Answer:

$\frac{21}{4}$ quarts

12 days

Step-by-step explanation:

Given that:

Amount of water leaked in 4 days = 3 quarts

To find:

Number of quarts leaked in 1 week?

Number of days taken for the leakage of 9 quarts of water?

Solution:

We can simply use unitary method or the ratio to find the answers of the questions asked in the statement.

As per question statement:

Amount of water leaked in 4 days = 3 quarts

Dividing by 4 on both sides:

Amount of water leaked in 1 day = $\frac{3}{4}$ quarts

Multiplying by 7 on both sides:

Amount of water leaked in 7 days = $\frac{3}{4}\times 7 = \frac{21}{4}$ quarts

Number of days taken for the leakage of 3 quarts = 4 days

Multiplying by 3 on both sides:

Number of days taken for the leakage of 3 $\times$ 3 = 9 quarts = 4 $\times$ 3 = <em>12 days</em>

6 0

2 years ago

When salt and water are combined, they form a salt or saline solution. How much ml of water must be added to 150 mL of an 80% sa

Vinvika [58]

Answer:

We must add 400 ml of water.

Step-by-step explanation:

We can use the following equation:

$C_{i}V_{i}=C_{f}V_{f}$

Where:

C(i) is the initial concentration of the solution (80%)
C(f) is the final concentration of the solution (30%)
V(i) is the initial volume (150 ml)
V(f) is the final volume

Now, we just need to solve the equation for V(f).

$V_{f}=\frac{C_{i}V_{i}}{C_{f}}$

$V_{f}=\frac{80*150}{30}$

$V_{f}=400\: ml$

Therefore, we must add 400 ml of water.

I hope it helps you!

3 0

2 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago