We know that the area of a semicircle = 1/2(πr^2)
r = the radius
We also know that the area of a rectangle = xy
x = width
y = length
In our problem,
r = w
x = w
y = w + 5
A(w) = w(w + 5) - 1/2(πw^2)
Let's simplify the right side of the function.
A(w) = w^2 + 5w - 1/2πw^2
Step-by-step explanation:
4x-(-7x+4.3)-1.6=x
4x+7x-4.3-1.6=x
11x-x=5.9
x=5.9/10=0.59 is your answer
since secθ = 1/cosθ
then secθ of cos(5/6) would be 1 / 5/6 = 6/5
4m-5
- 6m-7+2n
____________
-2m+2+2n
Answer: f(0)= -4, f(5)= 15, f(-3)= -7
Step-by-step explanation:
0 < 1, so plug into x-4. 0-4=-4
5> 1, so plug into 3(x). 3*5=15
-3<1, so plug into x-4. -3-4=-3+(-4)= -7