X>1 x<-1 has no solution why

1 answer:

3 0

Because there are no numbers that are greater than 1 but also less than -1. Numbers that are greater than one (x>1), are 2, 3, 4, 5, etc. Numbers that are less than negative one (x<-1) are -2, -3, -4, -5, etc. There is no overlap for these two numbers, therefore there is no solution that works for both of the inequalities.

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Match the vocabulary word to its correct definition.

Trava [24]

Answer:

1. Complex number.

2. Imaginary part of a complex number.

3. Real part of a complex number.

4. i

5. Multiplicative inverse.

6. Imaginary number.

7. Complex conjugate.

Step-by-step explanation:

1. Complex number: is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.

2. Imaginary part of a complex number: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.

3. Real part of a complex number: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.

4. i: a number defined with the property that 12 = -1.

5. Multiplicative inverse: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.

6. Imaginary number: any nonzero multiple of i; this is the same as the square root of any negative real number.

7. Complex conjugate: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.

4 0

3 years ago

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Svetach [21]

Step-by-step explanation:

k = 72

x= -81

..............