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Alexxx [7]
3 years ago
10

Divide three fourths ÷ two fifths

Mathematics
2 answers:
KengaRu [80]3 years ago
7 0
Your answer would be on eof the three
15/8
1.875
1 7/8
Hope this helps...
IRINA_888 [86]3 years ago
6 0
3/4 divided by 2/5 =    1 and 7/8
<span><span>
3/4 </span>÷ <span>2/5 </span></span><span>= 
</span><span><span><span>3 x 5=  15             7
-------    ---   =   1  ----
4 x 2=   8              8

Hope this helps!</span></span></span>
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Please help I’ll mark you as brainliest if correct!
Harrizon [31]

Answer:

45 matches up in enough hours yes so G!

The answer is g!

Step-by-step explanation:

Hope i helped! Your welcome!

7 0
3 years ago
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Alejandro made an error in the steps below when determining the equation of the line that is perpendicular to line 4x - 3y = 8 a
Ronch [10]

 

Hello:<span>
the equation is : y = ax+b
the slope is a : a×(4/3) = -1......( perpendicular to a line with a slope of   4/3)            because :     4x-3y =8...y=(4/3)x-8/3    )     </span>

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a = -3/4         y=(-3/4)x+b
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5 0
3 years ago
Heidi earns $11.50 per hour plus a bonus of $105 for the week. Her goal is to earn $650 for the week. Which equation
Stells [14]

Answer:

48 hours

Step-by-step explanation:

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6 0
3 years ago
Wilbur spends 2/3 of his income, share 1/12, and saves the rest. What part of his income does he save? Give the answer in simple
scoundrel [369]

Answer:

<em><u>1/4 of his income.</u></em>

Step-by-step explanation:

If Wilbur spends 2/3 of his income, 1/3 or 4/12 of it is left for other purposes (It is easier if everything has a common denominator of 12). And if he shares 1/12 of that remaining amount, there is 3/12 left. And when we simplify 3/12, we get <u>1/4</u>.

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7 0
3 years ago
9/20
NISA [10]

For this case we must find the solution of the following quadratic equation:

x ^ 2 + 5x + 7 = 0

Where:

a = 1\\b = 5\\c = 7

Then, the solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values:

x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}

By definition we have:i ^ 2 = -1

x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0
4 years ago
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