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Hatshy [7]
3 years ago
7

You wish to determine the GPA of students at your school. Describe what process you would go through to collect a sample if you

use a systematic sample.
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

simple random sampling

Step-by-step explanation:

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Please Help with these 3 questions Please
Pepsi [2]
For 14 the answer is -9
3 0
3 years ago
Help, I need the bottom three answered and I'm sorta stuck on four too. Not sure if it's right
amm1812
5. 15 yards = 13.716 meters, so 13.716 meters
6. 32.366 meters per second
7. 32÷2=16 and 16×60= 960, so it can eat 16 in one minute, and 960 in one hour.
Hope this helps!
7 0
3 years ago
According to data from the state blood program, 40 percent of all individuals have group A blood. If six individuals give blood,
Serjik [45]

Answer: 0.27648

Step-by-step explanation:

Given : The proportion of all  individuals have group A blood : p=0.040

Total individuals give blood : n= 6

Let X be the number of individuals have group A blood.

Since all individual are independent of each other.

X\sim Bin(n=6, p=0.40)

Formula : P(X=x)=^nC_xp^x(1-p)^{n-x} , where n= sample size , p = probability of getting success in each trial.

The probability that exactly three of the individuals have group A blood. :

P(x=3)= ^6C_3(0.40)^3(1-0.4)^3\\\\= \dfrac{6!}{3!3!}\times(0.40)^3(0.60)^3\\\\=0.27648

The probability that exactly three of the individuals have group A blood. is 0.27648

8 0
3 years ago
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
What is the area of this figure?
Anna71 [15]
Hope this can help you

3 0
3 years ago
Read 2 more answers
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