The present age of Jane is 45 years old and present age of her sister is 9 years old
<em><u>Solution:</u></em>
Let the present age of Jane be "x"
Let the present age of her sister be "y"
<em><u>Jane is 5 times older than her sister</u></em>
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)
Substitute eqn 1 in above equation
Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
Answer:
$793
Step-by-step explanation:
The amount of money in an account earning simple interest is given by the formula ...
A = P(1 +rt)
where P is the principal invested at rate r for t years.
__
Using the values given in the problem statement, the account balance can be found to be ...
A = $650(1 +0.055×4) = $650×1.22 = $793
There will be $793 in the account after 4 years.
Answer:2/20 =
2 ÷ 20 =
0.1 =
0.1 × 100/100 =
0.1 × 100% =
Step-by-step explanation:
google
Answer:
80/100
or
8/10
or
4/5
Step-by-step explanation: