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Trava [24]
3 years ago
6

fifty students are trying to raise at least 12,500 for a class trip. they have already raised 1,250. how much should each studen

t raise on average in order to meet the goal? write and solve the two step inequality for this problem
Mathematics
1 answer:
kompoz [17]3 years ago
6 0

Answer:

225

Step-by-step explanation:

12,500-1,250=11,250

11,250/50=225

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A man owns 3/4 of the share of a business and sells 1/3 of his
quester [9]

Given:

A man owns 3/4 of the share of a business and sells 1/3 of his  shares for Bir 10,000.

To find:

The value of the business in Bir.

Solution:

Let x be the value of the business.

It is given that a man owns 3/4 of the share of a business and sells 1/3 of his  shares for Bir 10,000.

x\times \dfrac{3}{4}\times \dfrac{1}{3}=10000

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3 0
3 years ago
Molly runs each morning once around a circular path in her neighborhood. if the diameter of the path is 1.4 miles, how far does
Lemur [1.5K]
To work out the distance of the path, you need to find out the circumference.
Formula for circumference = pi multiplied by the diameter

So you simply do:
pi multiplied by 1.4 miles

And you should get:
4.39822971503... miles

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Answer: 4.398 miles (to 3dp)
Hope the answer helps :)
6 0
3 years ago
Rob spent $38 on shirts. Tee shirts cost $4 and long sleeve shirts cost $5. If he bought a total of 8 then how many of each kind
KATRIN_1 [288]

Answer:

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3 years ago
Joel is designing a ramp for a bike trick. He draws this diagram. What is the value of x?
inn [45]

Answer:

x = -1

x = 5

Step-by-step explanation:

Use pythagorean theorem: a² + b² = c²

x² + (2x + 2)² = (2x + 3)²

Since these are quantities, you'll have to make them into quadratic equations.

(2x + 2)(2x + 2) = 4x² + 4x + 4x + 4

(2x + 3)(2x + 3) = 4x² + 6x + 6x + 9

x² + 4x² + 4x + 4x + 4 = 4x² + 6x + 6x + 9

Combine like terms

5x² + 8x + 4 = 4x² + 12x + 9

Move one side to set the equation equal to 0

x² - 4x - 5 = 0

Solve

x² - 5x + x - 5 = 0

x(x - 5) + 1(x - 5) = 0

(x + 1)(x - 5) = 0

x = -1, 5

<em>We</em><em> </em><em>can</em><em> </em><em>check</em><em> </em><em>that</em><em> </em><em>these</em><em> </em><em>are</em><em> </em><em>correct</em><em> </em><em>by</em><em> </em><em>plugging</em><em> </em><em>them</em><em> </em><em>in</em><em> </em><em>for</em><em> </em><em>x</em><em> </em><em>and</em><em> </em><em>seeing</em><em> </em><em>if</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>equal</em>

<em>For</em><em> </em><em>example</em>

<em>(</em><em>-1</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>2</em><em>)</em><em>²</em><em> </em><em>=</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>3</em><em>)</em><em>²</em>

<em>1</em><em> </em><em>=</em><em> </em><em>1</em>

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MaRussiya [10]
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