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3 years ago

The area of Jared’s computer room floor is 168 ft squared. The formula for area of a rectangle is a=l*

Mathematics

1 answer:

Anna [14]3 years ago

4 0

The answer is 12 divide 168 by 14 to get 12.

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Rewrite the equation in standard form 2x^2=5x+6

FrozenT [24]

Answer:

$2x^{2} =5x+6\\$

Step-by-step explanation:

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2 years ago

Which graph represents y= ^3 square root of x +2?

yaroslaw [1]

Answer:

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$y = \sqrt[2]{x}+2 \: will \: pass \: through \: (0 \:, 2) \: and \: ( - 8 \:, 0)$

Step-by-step explanation:

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2 years ago

Each cube in this figure is a -centimeter unit cube. How many cubes are in the prism? [Type your answer as a number.]

Annette [7]

Answer:

72 cubes

Step-by-step explanation:

One face of the cube has 12 cubes. A cube has 6 faces, 12 × 6 = 72. (12 cubes × 6 faces = 72 cubes)

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2 years ago

List all the factors of 14 from least to greatest. Enter your answer below,

Tasya [4]

Answer:

1, 2, 7, 14

Step-by-step explanation:

14 is a composite number. 14 = 1 x 14 or 2 x 7. Factors of 14: 1, 2, 7, 14.

8 0

3 years ago

A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order

Mazyrski [523]

Answer:

Feed 1, Soybean meal required = $\dfrac{2000}{3} \text{ lbs.}$

Feed 2, Corn meal required = $\dfrac{4000}{3} \text{ lbs.}$

Step-by-step explanation:

Total feed is <em>1 ton</em> i.e. <em>2000 lbs</em>.

Let <em>x</em> be the amount of Feed 1 required.

Feed 1 has $45\%$ of protein.

$\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)$

Then, amount of Feed 2 required = $(2000 - x) \text{ lbs.}$

Feed 2 has $15\%$ of protein.

$\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)$

As per question, total protein required is $25\%$ of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

$\Rightarrow x \times \dfrac{45}{100} + (2000 - x) \times \dfrac{15}{100} = 2000 \times \dfrac{25}{100}\\\Rightarrow 45x + 30000 - 15x = 50000\\\Rightarrow 30x = 20000\\\Rightarrow x = \dfrac{2000}{3}$

Feed 1 required = $\dfrac{2000}{3}\text{ lbs .}$

Feed 2 required = $2000 - \dfrac{2000}{3}\\$

$\Rightarrow \dfrac{4000}{3}\text{ lbs.}$

7 0

3 years ago