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Mariana [72]
3 years ago
9

HELP HELP EASY Use a calculator to approximate cos 43° and round to four decimal places.

Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:

0.731353701619170483287543608275622403378...

Step-by-step explanation:

cos((43 π)/180)

UwU

It's verified you can trust

<h2><u>0.7315</u></h2>

Is what you needed

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Which number is a factor of 16 but not a multiple of 8 Answer Choices: 6,4,12,10
eduard

the answer to the question is 4

3 0
4 years ago
What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

3 0
3 years ago
Read 2 more answers
(-4q^2-22q+12)/(2q+1) Please show working Need help ASAP! I will be very grateful for help!
jasenka [17]
First factor (-4q^2-22q+12), and you end up with −2(q+6)(2q−1)now rewrite your expression as: −2(q+6)(2q−1)/(2q+1)
unfortunately you can't simplify this any further.  
3 0
4 years ago
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Help Please! I need help on this quiz
astra-53 [7]

Answer:

x=42.5

Step-by-step explanation:

triangle inscribed in semicircle is right

2x+5=90

2x=85

x=42.5

if my answer helps please mark as brainliest.

8 0
4 years ago
The question is, "Find the volume of the bodies given in the figures below, which have a hole along their entire length." How do
aniked [119]

Answer:

1782 cm³

Step-by-step explanation:

First, you measure the volume of the cuboid as a whole which is length x breadth x height, 9 x 12 x 18 = 1944 cm³. Then measure the volume occupied by the space, 3 x 3 x 18 since the hole runs along the entire length = 162 cm³.

Then you subtract the volume occupied by the hole from the volume of the cuboid in total, 1944 - 162 = 1782 cm³

4 0
3 years ago
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