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3 years ago

Area of a triangle with a base length of 4in and a height of 9in

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

18 inches sqa-wared. "Nailed it!"
$4 \times 9 = 36 \\ 36 \div 2 = 18$

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If LM = 20 cm, and PQ = 16 cm, what is the length of RM, in centimeters?

LuckyWell [14K]

Answer:

RM = 12 cm

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

Assuming 20 is the hypotenuse cus there is no picture:

$a^{2} + 16^{2} = 20^{2}$

$a^{2} +256 = 400$

$a^{2} = 144$

$a=144$

If It's not the hypotenuse:

$16^{2}+ 20^{2} =c^{2}$

$256+400 =c^{2}$

$656=c^{2}$

$c = 25.61249695$

But I find it unlikely that 20 wasn't the hypotenuse so ignore that unless it applies.

Hope this helped. :0)

5 0

2 years ago

Use the cubic model y = 5a3 - 2a2 + a - 45 to find the value of y when x = 4.

Naddik [55]

Assuming 5a3 equals 5a^3, and the same for everything else, you would plug in 4 for a, so 5(4)^3 - 2(4)^2 + 4 - 45, which equals 247.

3 0

2 years ago

How to find the θ in this equation: tan(θ+16°)=1/tan(θ+60°) by using the trigonometric identities?thanks

DedPeter [7]

Answer:

$\huge \theta =7°$

Step-by-step explanation:

$tan( \theta + 16 \degree) = \frac{1}{tan( \theta + 60 \degree) } \\ tan( \theta + 16 \degree) =cot( \theta + 60 \degree) \\ tan( \theta + 16 \degree) = tan \{90 \degree - (\theta + 60\degree) \} \\ \theta + 16 \degree = 90 \degree - \theta - 60\degree \\ \theta +\theta = 30 \degree - 16\degree \\2 \theta = 14 \degree \\ \theta = \frac{14 \degree}{2} \\ \huge \red{ \boxed{\theta =7 \degree}}$

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2 years ago

What’s 1+1? Is it 929? Uwu

Allisa [31]

Answer:

No it's 2 Lol not 929 UwU

3 0

2 years ago

Determine whether the equation represents a direct variation. If it does, find the constant of variation. 2y=5x+1

coldgirl [10]

It does represent a direct variation.

Direct variation: y = kx
y varies directly with x

Your equation 2y = 5x + 1 is in the form of y = kx but we need to divide out the 2 from 2y so we have the following
2y = 5x + 1
2y / 2 = 5 x/ 2 + 1/2
y = 5x / 2 + 1/2
y = kx
k = 5/2
k = constant of variation = 5/2

6 0

2 years ago

Read 2 more answers