This is a cube root, so we look for factors of 162 which are perfect cubes.
Find the prime factors of 162:-
162 = 2 * 3 * 3 * 3* 3
27 = 3^3 is a perfect cube
162 = 6 * 27
so ^3√ 162 = ^3√6 * ^3√27 = ^3√6 * 3
so the simplest form is 3 ^3√6
Answer:
27 is a factor of 162. C on edge
Step-by-step explanation:
202
So it has to end in 2 because 20t+22 will always be a 2.
day1:
17x1+49=66
no 2
day2:
17x2+49=83
odd
day3:
D=100
day4:
day5:
D=134
etc
keep adding 17 to D until you get one that ends in 2
D=202
A=202
(P,O)(M,N)(M,P)(N,O)
brainliest pleeez
In ∆BCE
Opposite side to <E=BC
Opposite side to <B=EC
