Answer:
0.1536
Step-by-step explanation:
The computation of probability that the building failure will occur over its life is shown below:-
P(building failure) is

now we will solve the above equation
= 0.18 - 0.0264
After solving the above equation we will get
= 0.1536
Therefore for computing the probability that the building failure will occur over its life we simply applied the above formula.
Answer:14
Step-by-step explanation:
Answer:
x = -1 and y = -1
Step-by-step explanation:
to solve this equation we say
let
2x-5y=3.......................................... equation 1
4y-x=-3............................................equation 2
from equation 2
4y-x=-3............................................equation 2
4y + 3 = x
i.e
x = 4y + 3 ............................................. equation 3
put x = 4y + 3 in equation 1
2(4y +3) - 5y = 3
8y + 6 -5y = 3
3y +6 = 3
3y= 3-6
3y -3
divide both sides by the coefficient of y which is 3
3y/3 = -3/3
y = -1
put y = -1 into equation 3
x = 4y + 3 ............................................. equation 3
x = 4(-1) + 3
x = -4 + 3
x = -1
therefore the value of x = -1 and y = -1 respectively
By definition the area of a rectangle is:
A = l * w
Where,
l: long
w: width
So we have to clear the width:
w = A / l
Substituting the values:
w = (234) / (18) = 13
w = 13 feets
answer
the width, in feet, of the room is 13
Answer:
Step-by-step explanation:
Let assume that the volume = 88 cubic feet
Then:
The construction cost now is:

Now, to determine the minimum cost:
Now;