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3 years ago

Find the pair of similar triangles shown . find the length of side h .

Mathematics

1 answer:

kupik [55]3 years ago

3 0

$\frac{21}{h} = \frac{6}{7}$

6*h = 21*7
6h = 147
h = 24,5

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What's the area of the trapezoid

BlackZzzverrR [31]

46.5cm squared I believe
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3 years ago

If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI

Vikentia [17]

Answer:

The value is $y = \$ 225$

Step-by-step explanation:

From the question we are told that

The amount charge per year is $k = \$ 200$

The number of members it will have at this amount is $n = 50$

The amount amount increase that will lead to the loss of a single member is $z = \$ 5$

Generally the total amount the club would obtain from its members is mathematically represented as

$I = Amount \ due\ paid * Number \ of members$

Now let x denote the number of member lost

Hence

$I = (k + zx) (n-x )$

=> $I = (200 + 5x) (50-x )$

=> $I = 10000+50x-5x^2$

Thus the number of members that be removed to give the maximum income from dues is obtained by differentiating the above equation and equating it to zero

$\frac{dI}{dx} = 50-10x$

=> $x = 5$

So from $I = (200 + 5x) (50-x )$ we have

$I = (200 + 5 (5)) (50-5 )$

$I = \$ 10125$

So the amount the club should charge is

$y = \frac{10125}{50 - 5}$

$y = \$ 225$

7 0

3 years ago

Please help quickly Evaluate the expression: -|5+(2-8)|+|7(2-8)|

DanielleElmas [232]

$\displaystyle\\-\Big|5+(2-8)\Big|+\Big|7(2-8)\Big|=\\\\=-\Big|5+(-6)\Big|+\Big|7\times(-6)\Big|=\\\\=-\Big|-1\Big|+\Big|-42\Big|=\\\\=-(+1)+42=\\\\=-1+42=\boxed{\bf41}$

4 0

2 years ago

Read 2 more answers

Please help me! Thank you

Yuki888 [10]

Answer:

Anne

Step-by-step explanation:

The expression cannot be simplified anymore, but it can be laid out correctly.

The greatest number for the exponents should come first, so Anne is the one who laid it out correctly.

Hope it helps!!

Let me know if I'm wrong...

3 0

2 years ago

A student thinks that the regular pentagon in the diagram

Nadya [2.5K]

Answer:

Step-by-step explanation:

The student must have thought that every single arrowhead is a line of symmetry, so since there are 10 arrowheads, there must be 10 lines of symmetry. This is incorrect because if you look closely at the diagram, each line has 2 arrowheads, so the student is overcounting by a factor of 2. They should have just counted the number of lines, not arrowheads. Therefore, there must be 10/2 = 5 lines of symmetry, not 10. Hope this helps!

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2 years ago