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tangare [24]
2 years ago
7

. The dimensions of a triangle are shown below. What is the area of the triangle?

Mathematics
1 answer:
quester [9]2 years ago
5 0

Step-by-step explanation:

pls put the image as well becoz the dimensions are not shown

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8 0
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I need help with this ASAP plzzzzz
miss Akunina [59]

Answer:

23. \frac{4\sqrt{3} }{3}

24. \frac{7\sqrt{3}}{3}

25. 6\sqrt{3}

26. \frac{10\sqrt{3} }{3}

27.  14

28. 4\sqrt{3}

Step-by-step explanation:

To solve these i used SOHCAHTOA

sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}

23.

Find the missing side using Tangent

tan(30)=\frac{x}{4}

4*tan(30)=x

\frac{4\sqrt{3} }{3}

24.

Find the missing side using Tangent

tan(30)=\frac{x}{7}

7*tan(30)=x

\frac{7\sqrt{3}}{3}

25.

Find the missing side using Tangent

tan(30)=\frac{x}{18}

18*tan(30)=x

6\sqrt{3}

26.

Find the missing side using Tangent

tan(30)=\frac{x}{10}

10*tan(30)=x

\frac{10\sqrt{3} }{3}

27.

Find the missing side using Tangent

tan(30)=\frac{x}{14\sqrt{3} }

(14\sqrt{3}) *tan(30)=x

14

28.

Find the missing side using Tangent

tan(30)=\frac{x}{12}

12*tan(30)=x

4\sqrt{3}

5 0
3 years ago
12433333666 *5ii888888888888888888888<br> 6
Neko [114]

Answer:

7.321852048×10³⁰

Step-by-step explanation:

5 0
2 years ago
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