Answer:
7/12 OR 0.58 (2.d.p)
Step-by-step explanation:
Product means that the two rational numbers are being multiplied to get 7.
The question also tells us that one of them is 12. Therefore we can write an equation to express this information where we represent the unknown rational number using the letter 'r':
r x 12 = 7
Rearrange to find r:
r x 12 / 12 = 7 /12
r = 7/12 = 0.5833....
= 0.58 (2.d.p)
Hope this helped!
Answer:
(3, 1.7)
Step-by-step explanation:
The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.
Two lines are perpendicular if the product of their slopes is -1.
The slope of the line joining D(0,0), F(3,7) is:

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

The slope of the line joining E(7,0), and F(3,7). is:

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

The point of intersection of equation 1 and equation 2 is the orthocenter. Solving equation 1 and 2 simultaneously gives:
x = 3, y = 1.7
Answer:
Greater than.
Step-by-step explanation:

Answer:
13. 10a^4b²
14. -5y³ + 35y² - 10y
Step-by-step explanation:
Question 13:
(5a³b) (2ab) =
=10a^4b²
Question 14:
5y (-y² + 7y - 2) =
= -5y³ + 35y² - 10y
Hope this helps!
Answer:
Inequalities are,
y ≥ 4x + 2
y ≥ 2
Step-by-step explanation:
Solid yellow line of the graph attached passes through two points (0, -2) and (1, 2).
Let the equation of this line is,
y = mx + b
Slope of the line = 
m = 
m = 4
Y-intercept 'b' = -2
Equation of the line will be,
y = 4x - 2
Since shaded area is on the left side of this solid line so the inequality representing this region will be,
y ≥ 4x - 2
Another line is a solid blue line parallel to the x-axis.
Shaded region (blue) above the line will be represented by,
y ≥ 2
Therefore, the common shaded area of these inequalities will be the solution of the given inequalities.