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Karo-lina-s [1.5K]
3 years ago
7

I'LL GIVE YOU 35 POINTSSS HELP MEEE I NEED ASSISTANCE

Mathematics
1 answer:
Furkat [3]3 years ago
3 0
I hope this helps you

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What are the square number factors of 56?​
balandron [24]

Answer:

2,4,7,8,14,and 28

7 0
2 years ago
Help I need the answers in 20 minutes
Gelneren [198K]

2. 5 hours

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4. 9.5 hours. If it has to be whole numbers, 10 hours

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6 0
3 years ago
Read 2 more answers
PLEASE HELP I REALLY NEED IT
Aleonysh [2.5K]

Answer:

9. Force is required to change an object velocity.Force is equal to mass times acceleration.

10.  Force acting on object are paired with equal and opposite forces

Step-by-step explanation:

9.

Newton's 2nd law states that force is a product of mass and acceleration.In this case, the force of friction is causing deceleration of the ball.This is an example of rolling friction.Acceleration of the ball depends directly on this friction but indirectly on its mass.

10.

From Newton's 3rd Law ,for every action there is an equal and opposite reaction.The astronaut throwing the ball will experience the effect of an external force againts his own which is equal  and  in the opposite direction to the force she applied.This is why the astronaut moves backward but slower.

3 0
3 years ago
Find the 10th term of geometric sequence 3,15,75,375
Bess [88]

Answer:


Step-by-step explanation:

In a geometric sequence, the next term is a constant times the previous term. This constant is determined by dividing the second term by the first, here giving 5. The remaining terms are checked to see that each is 5 times the previous. 75 is 15×5, 375 is 75×5.


Alternately, the nth term is first term times k^(n-1).

Here, that's 3×5^(10-1), 3×5^9=5859375

7 0
3 years ago
Which choice is the explicit formula for the following geometric sequence?0.5, -0.1, 0.02, -0.004, 0.0008, ...
Minchanka [31]
a_1=0.5\\a_2=-0.1\\a_3=0.02\\a_4=-0.004\\a_5=0.0008\\\\a_n=a_1\cdot q^{n-1}\\\\q=a_2:a_1\to q=-0.1:0.5=-0.2\\\\a_n=0.5\cdot(-0.2)^{n-1}=0.5\cdot(-0,2)^n\cdot(-0.2)^{-1}\\\\=0.5\cdot(-0.2)^n\cdot(-5)=-2.5\cdot(-0.2)^n\\\\\boxed{a_n=-2.5\cdot(-0.2)^n}
6 0
4 years ago
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