Given:
The given sets are:
Set a : 200, 104, 100, 160.
Set b: 270, 400, 483, 300, x.
Mean of set a: mean of set b= 3:8
To find:
The value of x.
Solution:
Formula for mean:
The mean of set of a is:
The mean of set of b is:
It is given that,
Mean of set a: mean of set b= 3:8
Isolate the variable x.
Divide both sides by 3.
Therefore, the value of x is 427.
Answer:
3/2x-2>5 1/2
Step-by-step explanation:
Two less than a number means we are subtracting 2, so we can write it into the equation as -2.
Since we dont know the value of x, we can just write 3/2 of x by multiplying 3/2 by x. So 3/2x. Also, since we are subtracting two from 3/2x, -2 comes after 3/2x.
Now, since it says that it is more than 5 1/2, we could use the greater than sign (>), to express that. So >5 1/2
Our final expression is 3/2x-2>5 1/2.
Hope this helps!
Answer: Answer with Step-by-step explanation:
Since we have given that
Cost of party per person = $20.
Let the number of friends be 'f'.
Let the cost of party be 'p'.
According to question, our equation becomes
p= 2f
So, if p = 100, then f = p/2 = 100/2 = 50 if f = 10, then, p = 2f = 2 • 10 = 20 If p = 300 then, f = 300/2 = 150, If f = 20, then, p = 2f = 2 • 20 = 40 So, Table as follows:
Number of friends cost of party
50 100
10 20
150 300
20 40
9514 1404 393
Answer:
C. define all variables
Step-by-step explanation:
Equations for word problems will depend on the problem. Not all of the equations will be linear equations. Even if they are, they are not necessarily easily written in any particular form, or easily solved when they are written in that form. The nature of the equations will depend on the problem.
One thing that must be done in any case is <em>define all variables</em>. It is usually a good idea to define the units of the variable(s) as well. Sometimes problems are posed with numbers in incompatible dimensions, or they may ask for an answer in dimensions different from those used in the given information. In order to avoid confusion and to be sure you have the desired answer, you need to make sure the variables and their dimensions are compatible with the solution process.
