$550 at 4% compounded daily for 13 years

Mathematics

2 answers:

natali 33 [55]3 years ago

6 0

:> HOLA QUE ASE? (人◕ω◕)

vichka [17]3 years ago

5 0

Answer:Sydney’s

Step-by-step explanation:

Rhrurjeuejej

You might be interested in

1/3 divided by 1/8 a, 1/24 b. 3/8 C. 2 and 2/3 d. 24

Degger [83]

The answer is B. 3/8

5 0

2 years ago

Read 2 more answers

What does the following expression mean? 7! A. 7+6+5+4+3+2+1 B. 7·6·5·4·3·2·1

frez [133]

Answer: B

Step-by-step explanation:

A factorial is multiplying the integer and all of the integers below it together.

3 0

3 years ago

To find the area of parallelogram RSTU, Juan starts by drawing a rectangle around it. Each vertex of parallelogram RSTU is on a

Llana [10]

The correct answer is C.

8 0

3 years ago

Read 2 more answers

Select the two values of x that are roots of this equation. 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$