All categories

2 years ago

Surri solved the equation x ^ 2 equals 49 and found that x equals 7 what error did Suro make

2 answers:

8 0

He spelled his name wrong. Just kidding.

I don't think he did anything wrong.

7^2= 49.

If you need anymore help, let me know.

Brainliest answer would be appreciated.

denpristay [2]2 years ago

7 0

It does not look like Suro even made an error. She took the square root of both sides to get x = 7, I don't see any problem here.

You might be interested in

What is the area of a rectangle that measures 9 cm by 4 cm

andrew-mc [135]

The answer would be 36

3 0

3 years ago

Which expression represents "the sum of 5 and b divided by two

DIA [1.3K]

Step-by-step explanation:

<u>Break down the word expression:</u>

The sum of 5 and b divided by two

the sum (+) of 5 and b (5 + b) divided by 2.

<u>Expression:</u>

$\frac{(b + 5)}{2}$

Parentheses represent that we need to add first, in order to divide the sum by 2.

5 0

2 years ago

Answer and explain please ILL MARK BRAINLIEST PLEASE HELP

Slav-nsk [51]

Answer:

8:30 am

Step-by-step explanation:

8 0

2 years ago

If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn

mash [69]

Let $a=\tan A$ and $b=\sin A$ . Then

$m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab$

$\implies m^2-n^2=4\tan A\sin A$

and

$mn=(a+b)(a-b)=a^2-b^2$

$\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}$

The expression under the square root can be rewritten as

$\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)$

Recall that

$\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A$

so that

$\tan^2A-\sin^2A=\sin^2A\tan^2A$

and assuming $\sin A>0$ and $\tan A>0$ , we end up with

$4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A$

so that

$m^2-n^2=4\sqrt{mn}$

as required.

5 0

2 years ago

In a random sample of n1 = 162 males, there are x1 = 63 people that have blue eyes. In a random sample of n2 = 333 females, ther

sesenic [268]

Answer:

z = 2.1784 > 1.96,

Reject the null hypothesis

Step-by-step explanation:

For the males:

n1 = 162, x1 = 63

P1 = x 1/ n1 = 0.3889

For the Females:

n2 = 333,

x2 = 97

P 2 = x2/n2

= 0.2913

P 1= P2 Null hypothesis

P 1 is not equal to P 2 alternative hypothesis

Pooled proportion:

P= (x1 + x2) /( n1+ n2)

= (63 + 97) / (162 + 333)= 0.3232

Test statistics :

Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)

0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)

=2.1784

c) Critical value :

Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960

Reject H o if z < -1.96 or if z > 1.96

d) Decision:

z = 2.1784 > 1.96,

Reject the null hypothesis

7 0

3 years ago