Answer:
The correct option is O B'
Step-by-step explanation:
We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.
Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.
In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.
Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).
I will attach a drawing with an example.
Finally, we only have to look at the vertices and its original distances to answer the question.
The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'
Answer:
2^5
explanation:
I did this already man this is easy
Answer:
-2
Step-by-step explanation:
The integer of - 2 is - 2 only as integers can be positive and negative whole numbers
Answer:
f(0)=6
Step-by-step explanation:
When representing function's values by set of ordered pairs, the first one correspond to the x value and the second to the image or "y" value.
When you read f(0) means "when x is 0" then the 6 is the value of the function or the image.
Answer:
8
Step-by-step explanation:
The numbers are 6 and 2x, then:
- 1/6 + 1/(2x) = 7/24
- 1/3 + 1/x = 7/12
- (x+3)/(3x) = 7/12
- 12(x+3) = 7*3x
- 12x + 36 = 21x
- 21x - 12x = 36
- 9x = 36
- x = 4
The other number is 2*4 = 8