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3 years ago

When writing routine requests, you should expect strong resistance from message recipients?

1 answer:

7 0

The statement above is FALSE. Business organisation require information to run smoothly. This information often has to be requested from others.
When writing routine requests you should expect little or no resistance from the recipient. Requests are used to coordinate work efforts and to maintain work relationships. Request making helps to retain goodwill with the recipient.

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Bertone's Office Supplies has large stores resembling warehouse environments, with racks stocked from floor to ceiling with diff

evablogger [386]

Answer:

The correct answer to the following question is category specialist.

Explanation:

Here Bertone's office supplies can be said as category specialist stores, these are those discount stores which specializes in particular product category. That's why these stores are also called discount specialist stores. The reason why these stores are able to offer low prices is because they are using their buying power to negotiate the terms and conditions like getting the supply at low prices.

4 0

3 years ago

QUESTION 10 of 10: You have been promoted to buyer for a mall-based fashion retailer. With your promotion, you will earn an addi

Gwar [14]

6.9% or 14.5%

Explanation:

I did the math

I belive 6.9% is the correct answer tho

8 0

2 years ago

The following information was taken from the records of Roland Carlson Inc. for the year 2020: income tax applicable to income f

Free_Kalibri [48]

Answer: uhhh d

Explanation:

5 0

3 years ago

Suppose the world population today is 7 billion, and suppose this population grows at a constant rate of 3% per year from now on

oksano4ka [1.4K]

Answer:

a) $P(t=100) = 7 e^{0.03*100}=140.599 billion$

b) $P(t=0) = 7 e^{0.03*0}=7 billion$

$P(t=1) = 7 e^{0.03*1}=7.21 billion$

$P(t=2) = 7 e^{0.03*2}=7.43 billion$

$P(t=10) = 7 e^{0.03*10}=9.45 billion$

$P(t=25) = 7 e^{0.03*25}=14.82 billion$

$P(t=50) = 7 e^{0.03*50}=31.37 billion$

c) Figure attached

d) Figure attached

Explanation:

The proportional model on this case would be given by:

$\frac{dP}{dt} = kP$

Where P is the population size, t the time on years and k a constant.

We can reorder this expression like this:

$\frac{dP}{P} = k dt$

If we integrate both sides we got:

$ln|P| = kt + C$

And using exponentials on both sides we got:

$P(t) = e^{kt} e^C = P_o e^{kt}$

Where $P_o=7 billion$ represent the initial amount for the starting year t=0.

The rate on this case is given $r =3\% = 0.03$ , so then our model would be given by:

$P(t) = 7 e^{0.03t}$

Part a

For this case we just need to replace t=100 and we got:

$P(t=100) = 7 e^{0.03*100}=140.599 billion$

Part b

For this case we have the following:

$P(t=0) = 7 e^{0.03*0}=7 billion$

$P(t=1) = 7 e^{0.03*1}=7.21 billion$

$P(t=2) = 7 e^{0.03*2}=7.43 billion$

$P(t=10) = 7 e^{0.03*10}=9.45 billion$

$P(t=25) = 7 e^{0.03*25}=14.82 billion$

$P(t=50) = 7 e^{0.03*50}=31.37 billion$

Part c

The graph is on the first figure attached.

Part d

If we take a log-log scale we have the following values

We need to exclude the point t=0 since the natural log for 0 is not defined.

ln 1 =0 , ln 2= 0.693, ln 10=2.30, ln 25 =3.22, ln 50= 3.91

The result would be the figure 2 attached. And we see a better result for the graph.

3 0

3 years ago

Fit-for-Life Foods reports the following income statement accounts for the year ended December 31.

Alenkinab [10]

Answer: Check attachment

Explanation:

Note that, in the attachment, the total expense was calculated as the addition of the selling expense and the general and administrative expenses. This will be:

= $49700 + $34110

= $83810

Operating income was calculated as:

= Gross profit - Total expenses

= $107200 - $83810

= $23390

Check the attachment for further details.

4 0

3 years ago