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Vesna [10]
3 years ago
12

AUPH stock jumped up 60%, then down 60% did it return the same price

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

No, it didn't return to the same price

Step-by-step explanation:

Let the initial stock price be 100

When it increased by 60%, it went to:

60% = 60/100 = 0.6

0.6 * 100 = 60

100 + 60 = 160

Then, from 160, it decreased by 60%, so it went to:

60% = 0.6

So,

0.6 * 160 = 96

Now,

160 - 96 = 64

So final price is 64. So, it didn't go back to original (100).

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
How much will you get paid if you work 28.5 hours for $7.75 per hour?
Wewaii [24]

Step-by-step explanation:

<h3>Answer:-</h3>

Here, Unitary Method is used. It tells:-

\bf{1 \ hour =} $ \bf{7.75}

\bf{28.5 \ hours =} $ \bf{(7.75 \times 28.5)}

$ \bf{220.875} is the answer.

Hope it helps :D

3 0
3 years ago
Which expression is equivalent to (3x^2-7)
Alexxx [7]

Answer:

x^2-2x+1

Hope this Helps! <3

8 0
2 years ago
Find the equation of the line that passes through (1,2) and is perpendicular to y=2x+3. Leave your answer in the form y=mx+c
zhenek [66]

Answer:

y = -1/2x + 5/2

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = 2x + 3. Its slope is 2. A line perpendicular to this one will have a slope of -1/2.

Plug this value (-1/2) into your standard point-slope equation of y = mx + b.

y = -1/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (1, 2). Plug in the x and y values into the x and y of the standard equation.

2 = -1/2(1) + b

To find b, multiply the slope and the input of x (1)

2 = -1/2 + b

Now, add 1/2 to both sides to isolate b.

5/2 = b

Plug this into your standard equation.

y = -1/2x + 5/2

This equation is perpendicular to your given equation (y = 2x + 3) and contains point (1, 2)

Hope this helps!

3 0
3 years ago
Solve for b: (1/t)=(1/a)+(1/b)
crimeas [40]

How to get answer by Mimiwhatsup:

Let's solve for b.

1/t = 1/a + 1/b

Step 1: Multiply both sides by t.

1= at+bt/ab

Step 2: Multiply both sides by ab.

ab=at+bt

Step 3: Add -bt to both sides.

ab+−bt=at+bt+−bt

ab−bt=at

Step 4: Factor out variable b.

b(a−t)=at

Step 5: Divide both sides by a-t.

b(a−t)/a−t = at/a−t

b= at/a−t



6 0
3 years ago
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