Answer:
AB = 2
BC = 2
A'B' = 6
B'C' = 6
Step-by-step explanation:
Answer: x= 18
Step-by-step explanation:
3x - 16 = 38
38 + 16 = 54
3x/3 = 54/3
X= 18
1,450 because you would plug 75 in for x
f(x)= 20(75)-50
Answer: $6,000
Step-by-step explanation: If set up correctly, the value of the car at the end of 2006 times 0.6 (because the car is losing 0.4 of its value, so it keeps 0.6 of its value) should get you the value of the car at the end of 2007.
The equation should look like this:
(value of the car at the end of 2006) x 0.6 = (value of the car at the end of 2007)
Then you substitute: (value at the end of 2006) x 0.6 = 3600
Then divide: (value at the end of 2006) = 0.6 ÷ 3600
Then substitute again: (value at the end of 2006) = 6,000
Hope this helped you! Feel free to ask me any questions!

now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.
so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.
therefore, we settle for the endpoints, 4 and 6,
f(4) =3 and f(6) = 7
doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.