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zmey [24]
3 years ago
7

An alloy is composed of nickel, zinc, and copper in a ratio of 7:2:9. How many kilograms of each metal are needed to make 3.6 kg

of this alloy?
Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer:

Nickel= 1.8 kg

Zinc= 0.4 kg

Copper= 1.8 kg

Step-by-step explanation:

7:2:9

7=nickel

2=zinc

9=copper

7+2+9=18

18×2=36

7×2=14 2×2=4 9×2=18

Divide by 10

14÷10=1.4 4÷10=0.4 18÷10=1.8

1.8+1.4+0.4= 3.6

1.8=nickel

0.4=zinc

1.8=copper

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100 POINTS! College Statistics
kirza4 [7]

(a) Collision claims tend to be skewed right because there are a few very large collision claims relative to the majority of claims.

These large collision claims skew the data to the right because they are outliers that draw the mean higher than it should be.

The answer cannot be "no large collision claims" or "many large collision claims" because then the data would not be skewed.

(b) Since there are two random samples comparing two means, we will be using a 2-Samp-T-Test. We will use Welch's approximate t-test, where we test the hypothesis that these two populations have the same mean.

We want to determine if 20-24 year old drivers have the same mean collision cost as 30-59 year old drivers.

(c) The null hypothesis is that <u>the mean claim of collision costs for 20-24 year old drivers is the same as the mean claim of collision costs for 30-59 year old drivers.</u>

We can also rewrite this as:

  • H₀: μ₁ = μ₂
  • where μ₁ is the mean collision claims for 20-24 year old drivers
  • and μ₂ is the mean collision claims for 30-59 year old drivers

The alternative hypothesis is that the <u>mean claim of collision costs for 20-24 year old drivers is higher than the mean claim of collision costs for 30-59 year old drivers</u>.

We can rewrite this as:

  • H₁: μ₁ > μ₂
  • Our variables have already been defined

(d) In order to calculate the p-value, we must find the test statistic first.

We can do so by using this formula:

  • \displaystyle t=\frac{x_1-x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}  }}

We are given these variables in the problem:

  • x_1=4590
  • s_1=2302
  • x_2=3670
  • s_2=2029
  • n_1=40
  • n_2=40

Substitute these variables into the formula for the test statistic.

  • \displaystyle t=\frac{4590-3670}{\sqrt{\frac{2302^2}{40} +\frac{2029^2}{40} } }

You can use the calculator to solve this expression, or plug the numbers into your calculator using: STAT - TESTS - 4:2-SAMPTTEST.

Your test statistic should be: t = 1.8962.

The calculator should also tell you the p-value; p = .0308.

(e) Since p = .0308 < α = .1, <u>reject</u> the null. We have convincing statistical evidence that the mean claim of collision costs for 20-24 year old drivers is higher than the mean claim of collision costs for 30-59 year old drivers.

4 0
2 years ago
PLEASE HELP! Will Give brainliest!
statuscvo [17]

Answer:

1

Step-by-step explanation:

definite integral from 0-2 of root x dx

root x = x^½

integral of x^½ = ⅔x^(3/2)

4 0
2 years ago
What city is located at 39 n and 75 w
Zigmanuir [339]
I think its Philadelphia hopes this helps...
7 0
3 years ago
2x+3y=11, solve for y
lesya [120]
Hope it helps with your work

4 0
3 years ago
Read 2 more answers
Hello everyone!
Ivan
After 1 year it is worth 108% of its original value
108% = 1.08
so 1.08 x 1000 = $1080

After 2nd year it is worth 92% of that $1080
92% = 0.92
so 0.92 x 1080 = $993.60
3 0
3 years ago
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