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4 years ago

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Paul has 57 oranges to share with Dwayne and Ashley. The number of oranges Paul gives to Dwayne is 3 more than five times the nu

mber of oranges he gives to Ashely. If Paul has no oranges left over,how many oranges does Paul give to Ashely?

1 answer:

bija089 [108]4 years ago

7 0

I believe is 32 sorry if is wrong

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Which graph comparing time and dollars would be best represented by an exponential function?

Rasek [7]

Answer:

x and y

Step-by-step explanation:

because it make sense

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3 years ago

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Does anyone know how to do this? And can you also help me with this problem, thank you :)

GenaCL600 [577]

<span>Multiply equation(2) with 4 so that coefficient of become same in both the equations(You can make coefficient of y same and can follow the following procedure.)
</span><span>* Subtract (3) from (1)
* </span>Divide both sides by -19
*Subtract 21 from both sides.
*Divide both sides by 4
so the solution is x= 3 and y= -7
Hope I helped you :)

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3 years ago

Jasmyn uses 42% of a gift card to buy groceries if she spent $67.20 on groceries, how much was on the gift card to begin with

lapo4ka [179]

Answer:

The card was worth $160.

Step-by-step explanation:

It is given that:

Percent of gift card used = 42%

Cost of groceries = $67.20

Let,

x be the total amount on gift card.

42% of x = 67.20

$\frac{42}{100}x=67.20$

0.42x = 67.20

$\frac{0.42x}{0.42}=\frac{67.20}{0.42}\\x=160$

Therefore,

The card was worth $160.

4 0

3 years ago

Jami can mow acre 1/6 in 8 minutes If her rate is constant, can Jami mow 1 1/2 acres in one hour? Explain your reasoning

LenaWriter [7]

Time taken by Jami to mow 1/6 acres is 8 minutes=8/60=2/15 hours.
Rate at which Jami is mowing will be:
rate=(number of acres)/(time)=(1/6)/(2/15)
=1/6÷2/15
=1/6×15/2
=5/4 acres/hour
=1.25 acres/hour
From above calculations we conclude that Jami cannot mow 1.5 acres in 1 hour

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3 years ago

Read 2 more answers

A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes

Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to $180^{o}$ . The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to $180^{o}$ .

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos C

So that;

$7^{2}$ = $6^{2}$ + $(6.5)^{2}$ - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

= 29.25

Cos C = $\frac{29.25}{78}$

= 0.375

C = $Cos^{-1}$ 0.375

= 67.9757

C = $68^{o}$

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{6.5}{Sin B}$ = $\frac{7}{Sin 68}$

SIn B = $\frac{6.5 *Sin 68}{7}$

= 0.861

B = $Sin^{-1}$ 0.861

= 59.43

B = $59.4^{o}$

Thus to determine the value of A, we have;

A + B + C = $180^{o}$

A + $59.4^{o}$ + $68^{o}$ = $180^{o}$

A = $180^{o}$ - 127.4

= 52.6

A = $52.6^{o}$

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

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2 years ago