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posledela
3 years ago
10

Please help!!!!!!!!!!!!

Mathematics
1 answer:
frosja888 [35]3 years ago
6 0

Answer:

<h2>all 3</h2>

Step-by-step explanation:

The equilateral triangle is a triangle in which all three sides are equal.

Therefore your answer is all 3.

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How manyy solutions does this system of equations have? explain how you know y + 2x = 5 y = 3x + 5
tigry1 [53]

Answer:

(-5, -10)

Step-by-step explanation:

y+2x = 5y

==>2x=4y

x=2y

5y=3(2y)+5

==>

y = -5

x = -10

==>

one solution

5 0
3 years ago
This is big ideas work pls show how u do it so i know
Komok [63]

Answer:

(5,-1)

Step-by-step explanation:

7 0
2 years ago
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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
Ugo [173]

Answer:

Side\ B = 6.0

\alpha = 56.3

\theta = 93.7

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with \alpha, \beta, \theta

[See Attachment for Triangle]

A = 10cm

C = 12cm

\beta = 30

What the question is to calculate the third length (Side B) and the other 2 angles (\alpha\ and\ \theta)

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

B^2 = A^2 + C^2 - 2ABCos\beta

Substitute: A = 10,  C =12; \beta = 30

B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30

B^2 = 100 + 144 - 240*0.86602540378

B^2 = 100 + 144 - 207.846096907

B^2 = 36.153903093

Take Square root of both sides

\sqrt{B^2} = \sqrt{36.153903093}

B = \sqrt{36.153903093}

B = 6.0128115797

B = 6.0 <em>(Approximated)</em>

Calculating Angle \alpha

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute: A = 10,  C =12; B = 6

10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 180 - 144 *Cos\alpha

Subtract 180 from both sides

100 - 180 = 180 - 180 - 144 *Cos\alpha

-80 = - 144 *Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}

\frac{-80}{-144} = Cos\alpha

0.5555556 = Cos\alpha

Take arccos of both sides

Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)

Cos^{-1}(0.5555556) = \alpha

56.25098078 = \alpha

\alpha = 56.3 <em>(Approximated)</em>

Calculating \theta

Sum of angles in a triangle = 180

Hence;

\alpha + \beta + \theta = 180

30 + 56.3 + \theta = 180

86.3 + \theta = 180

Make \theta the subject of formula

\theta = 180 - 86.3

\theta = 93.7

5 0
3 years ago
Dividing a whole number by a unit fraction results in a:
Alex Ar [27]

Answer:

each unit being divided into smaller parts

Step-by-step explanation:

7 0
2 years ago
Some one help please! Have sitting for 1 hour and don’t know this. Its new to me. Aack. I will put u as brainliest if you answer
Sever21 [200]
For the first one to find the total area you have to first find the area of the triangle 1/2(10x12.5)=62.5 and then the square (13.4x12.5)=167.5 which is 10468.75 totaled
8 0
3 years ago
Read 2 more answers
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