Answer:
i think the answer is B because 3/4 is more than 2/3
Answer: they would have 216.06 square meters of grassy area left in the park
Step-by-step explanation: if you start with 150.04 and add 37.51 by removing trees and shrubs you would have 187.55 and then if you added 82.70 more square feet by removing the unused Picnic pavilion you would have 270.25 square meters of grassy area. Then lastly is you update the playground by reducing 54.19 square meters ( 270.25-54.19) you would get left with 216.06 square meters of grassy area :)
tangent is less than 0 or tan(θ) < 0, is another way to say tan(θ) is negative, well, that only happens on the II Quadrant and IV Quadrant, where sine and cosine are different signs, so we know θ is on the II or IV Quadrant.
![\bf \pm\sqrt{3^2-2^2}=a\implies \pm\sqrt{5}=a\implies \stackrel{\textit{II Quadrant}}{-\sqrt{5}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-\sqrt{5}}}{\stackrel{hypotenuse}{3}}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cpm%5Csqrt%7B3%5E2-2%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B5%7D%3Da%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BII%20Quadrant%7D%7D%7B-%5Csqrt%7B5%7D%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20cos%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B-%5Csqrt%7B5%7D%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B3%7D%7D~%5Chfill)
24 rounded to the nearest 7
Answer:
it is a commutative property
