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2 years ago

Triangle ABC has a perimeter of 22cm I WILL MARK YOU AS BRAINLIEST

Mathematics

1 answer:

Andreyy892 years ago

7 0

Answer:

Step-by-step explanation:

Number of vertices

Variable constraints

a>0 and b>0

Diagonal lengths

(data not available)

Height

Area

A = (a b)/2

Centroid

x^_ = (a/3, b/3)

Mechanical properties:

Area moment of inertia about the x-axis

J_x invisible comma x = (a b^3)/12

Area moment of inertia about the y-axis

J_y invisible comma y = (a^3 b)/12

Polar moment of inertia

J_zz = 1/12 a b (a^2 + b^2)

Product moment of inertia

J_x invisible comma y = -1/24 a^2 b^2

Radii of gyration about coordinate axes

r_x = b/sqrt(6)

r_y = a/sqrt(6)

Distance properties:

Side lengths

a | sqrt(a^2 + b^2) | b

Hypotenuse

sqrt(a^2 + b^2)

Perimeter

p = sqrt(a^2 + b^2) + a + b

Inradius

r = 1/2 (-sqrt(a^2 + b^2) + a + b)

Circumradius

R = 1/2 sqrt(a^2 + b^2)

Generalized diameter

sqrt(a^2 + b^2)

Convexity coefficient

χ = 1

Mean triangle area

A^_ = (a b)/24

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Step-by-step explanation:

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$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

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$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

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