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2 years ago

15

What is 1 + 57 = ? help this is hard!

2 answers:

blagie [28]2 years ago

6 0

Answer:

58 LOL or is it 109? I don't know it's too hard for me to figure out but I think it's 58

Anvisha [2.4K]2 years ago

3 0

79 , this took some time but I figured it out

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Can anbody help? I need this to pass my exam

melamori03 [73]

Answer:

the third one

Step-by-step explanation:

search up 30 - 60 - 90 triangle rule for references

6 0

3 years ago

B^-3 = 1/64 what equals b

s2008m [1.1K]

64=2*2*2*2*2*2=2⁶

B⁻³=1/64
1/B³=1/2⁶
B³=2⁶
B=∛2⁶=2⁶/³=2²=4

Answer: B=4

5 0

3 years ago

A rental car company has noticed that the distribution of the number of miles customers put on rental cars per day is skewed to

kodGreya [7K]

Using the Central Limit Theorem, the correct option is:

(c) Average number of miles put on a rental car per day across 25 customers.

--------------------------

The Central Limit Theorem states that, for a normally distributed variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means of size m are approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

The interpretation related to this problem is that the larger the sample size, the smaller the standard deviation.
Thus, among the options, the largest sample is 25, thus, option c will have the smallest standard deviation.

A similar problem is given at brainly.com/question/23088374

5 0

2 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

3 years ago

A cyclist travels 17 km from home to the park.

kupik [55]

Answer:

34 km/h

Step-by-step explanation:

speed = distance/time

Distance = 17km

Time = 0.5 or 1/2 hours because it's 30 minutes between 17:15 to 17:45, and 30 minutes is a half of an hour and you want km over hours

So

speed = 17/0.5

speed = 34 km/h

7 0

3 years ago