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3 years ago

A truck moves 60 kilometers east from point A to point

Physics

2 answers:

CaHeK987 [17]3 years ago

6 0

The total distance is 60*2-15=105 kilometers, and the total displacement is 15 kilometers east.

sergiy2304 [10]3 years ago

3 0

Answer:

Option A is the correct answer

Explanation:

Let i represent positive X axis ( east).

A truck moves 60 kilometers east from point A to point B

Displacement = 60 i km

Distance = 60 km

At point B, it turns back west and stops 15 kilometers away from point A

Displacement = -45 i km

Distance = 45 km

Total

Displacement =60 i - 45 i = 15 i km Towards east

Distance = 60+ 45 = 105 km

Option A is the correct answer

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2. Human Impact on the Environment

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3 years ago

what is the magnitude of the vector described below? 13 m/s to the east a. east b. meters per second c. 13 m/s d. meters

Katen [24]

Answer:

Explanation:

Magnitude of any quantity is the measurable value of the quantity. While the direction of the given quantity is the specific pointing direction of position or the angle at which it move.

The magnitude of the vector described below? 13 m/s to the east will be 13 m/s

While the direction will be eastward.

Therefore, the magnitude is 13 m/s

The correct answer is option C

3 0

3 years ago

1) Si un mango cae a una velocidad de 75m/s y tarda 26 seg. en caer. ¿ Cuál habrá sido la velocidad con qué el mango llegó al su

Lyrx [107]

Answer:

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

Explanation:

El mango experimenta un movimiento de caída libre, es decir, un movimiento uniformemente acelerado debido a la gravedad terrestre, despreciando los efectos de la viscosidad del aire y la rotación planetaria. Entonces, la velocidad final del mango, es decir, la velocidad con la que llega al suelo, se puede determinar mediante la siguiente fórmula cinemática:

$v = v_{o}+g\cdot t$ (1)

Donde:

$v_{o}$ - Velocidad inicial, en metros por segundo.

$v$ - Velocidad final, en metros por segundo.

$g$ - Aceleración gravitacional, en metros por segundo al cuadrado.

$t$ - Tiempo, en segundos.

Si sabemos que $v_{o} = -75\,\frac{m}{s}$ , $g = -9.807\,\frac{m}{s^{2}}$ y $t = 26\,s$ , entonces la velocidad final del mango es:

$v = v_{o}+g\cdot t$

$v = -75\,\frac{m}{s}+\left(-9.807\,\frac{m}{s} \right)\cdot (26\,s)$

$v = -329.982\,\frac{m}{s}$

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

8 0

2 years ago

A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080

deff fn [24]

Answer:

Speed of 0.08 kg mass when it will reach to the bottom position is 1.94 m/s

Explanation:

When rod is released from rest then due to unbalanced torque about the hinge the system will rotate

Now moment of inertia of the system is given as

$I = \frac{ML^2}{12} + \frac{m_1L^2}{4} + \frac{m_2L^2}{4}$

now we have

$M = 0.120 kg$

$m_1 = 0.02 kg$

$m_3 = 0.08 kg$

now we have

$I = \frac{0.120(0.90)^2}{12} + \frac{0.02(0.90)^2}{4} + \frac{0.08(0.90)^2}{4}$

so we have

$I = 8.1 \times 10^[-3} + 4.05 \times 10^[-3} + 0.0162$

$I = 0.02835$

now by energy conservation we can say work done by gravity must be equal to change in kinetic energy

so we have

$\frac{1}{2}I\omega^2 = m_1g \frac{L}{2} - m_2 g\frac{L}{2}$

$\frac{1}{2}(0.02835)\omega^2 = (0.08 - 0.02)(9.81)(0.45)$

$\omega = 4.32 rad/s$

Now speed of 0.08 kg mass when it reaches to bottom point is given as

$v = \omega \frac{L}{2}$

$v = 4.32 (0.45)$

$v = 1.94 m/s$

3 0

3 years ago

The Doppler effect is the apparent change in frequency due to the movement of the source and the observer. This means an object

Alekssandra [29.7K]

Answer:

Doppler effect changes the wavelength of the light emitted, depending upon whether source is moving away or coming towards the observer(detector).

Explanation:

Doppler effect in light is actually a relativistic effect but somewhat similar to the one which happens in sound waves.

When the source is moving away from the detector, the wavelength of the light emitted from the source appears to be increased as seen by the detector, as a result the frequency decreases(we know that frequency of light= speed of light/wavelength of light. Here speed of light is constant and frequency of light is inversely proportional to its wavelength)

Due to this decrease in frequency the light emitted from the source appears more red, since red color is on low frequency side in the electromagnetic spectrum.

Similarly for the source moving towards the detector, the wavelength appears to be decreased, thereby resulting in increase in frequency and the source appears blue. The shift in frequency is known as doppler shift.

The shift in frequency when the source is moving away is known as redshift and the one where the source is moving towards detector is known as blueshift

4 0

3 years ago