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weqwewe [10]
3 years ago
12

What is the correct defenition of velocity

Physics
2 answers:
lina2011 [118]3 years ago
8 0

Velocity is the time rate of change of displacement.

MA_775_DIABLO [31]3 years ago
6 0

Velocity is speed plus direction

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What is the fundamental frequency of a 0.003 kg steel piano wire of length 1.3 m and under a tension of 2030 N? Answer in units
Sladkaya [172]

a) 277.5 Hz

b) 61.6 Hz

Explanation:

a)

Stationary waves are the waves produced on a string: these are waves that do not propagate through space, since they travel only back and forth along the string.

These waves can have different frequencies, depending in how many segments of the string they vibrate.

The frequency of the fundamental mode of vibration (the one having only two nodes at the ends of the string) is called fundamental frequency, and it is given by:

f_1=\frac{1}{2L}\sqrt{\frac{T}{m/L}}

where

L is the length of the spring

T is the tension

m is the mass of the string

For the steel piano wire in this problem:

T = 2030 N

L = 1.3 m

m = 0.003 kg

Therefore, the fundamental frequency is

f_1=\frac{1}{2(1.3)}\sqrt{\frac{2030}{(0.003)/(1.3)}}=277.5 Hz

b)

An organ pipe is a closed-air tube, which is open at one end and close at the other end.

For a closed-open air tube, the wavelength of the fundamental mode of vibration is equal to 4 times the length of the tube:

\lambda_1 = 4 L

In this case, the length of the tube is

L = 1.38 m

So the fundamental wavelength is

\lambda_1 = 4(1.38)=5.52 m

The relationship between frequency and wavelength for a sound wave is

f_1=\frac{v}{\lambda_1}

where in this case:

v = 340 m/s is the speed of sound

\lambda_1 = 5.52 m is the fundamental wavelength

Solving for f1, we find the fundamental frequency:

f_1=\frac{340}{5.52}=61.6 Hz

4 0
3 years ago
A constant 10.0-N horizontal force is applied to a 20.0-kg cart at rest on a level floor. If friction is negligible, what is the
Otrada [13]

Answer:

2.83 m/s

Explanation:

Given:

Mass of the cart (m) = 20.0 kg

Initial velocity of the cart (u) = 0 m/s

Final velocity (v) = ? m/s

Displacement of the cart (S) = 8.0 m

Horizontal force acting on the cart (F) = 10.0 N

Surface is frictionless. So, only horizontal force is the force acting on the cart.

Now, as per work-energy theorem, the work done by the net force acting on a body is equal to the change in the kinetic energy of the body.

Here, the work done by the horizontal force is given as:

W_{net}=FS=(10\ N)(8.0\ m)=80\ Nm

The change in kinetic energy is given as:

\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}(20.0\ kg)(v^2-0)\\\\\Delta K=10v^2

Now, from work-energy theorem:

\Delta K=W_{net}\\\\10v^2=80\\\\v^2=\frac{80}{10}\\\\v=\sqrt{8}=2.83\ m/s

Therefore, the speed of the cart when it has been pushed 8.0 m is 2.83 m/s.

5 0
3 years ago
Which term describes the object that a satellite revolves around?
m_a_m_a [10]

The object that a satellite revolves around is the <em>central body</em> of the system. <em>(C)</em>

For example:

-- The central body of the solar system is the Sun.

-- The central body for TV satellites, GPS satellites, weather satellites, and the International Space Station is the Earth.

-- The central body for Phobos and Deimos is Mars.

This should be a pretty easy question to answer by elimination, when you notice that "Orbit", "Period", and "Rotation" are not "Bodies".

6 0
2 years ago
Read 2 more answers
Jacques is trying to put a screw into a hard piece of wood, but it is too difficult for him to turn. Which of the following woul
solniwko [45]

Answer:

A. It is the only one that makes sense

Explanation:

3 0
3 years ago
An 80kg parachutist jumps out of an airplane. Neglecting air friction, how fast will he be going after a 10 second free fall?
olganol [36]
If he is jumping you are adding force which means that you will be falling twice as fast
6 0
3 years ago
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