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3 years ago

The sum of two numbers is 12. The first number,x, is twice the second number ,y,

1 answer:

3 0

Judging by the question at hand I generated this equation.
x+y=12
x=2y

I begin this question by plugging in the x=2y into the equation for x.
So the new equation should be 3y=12. I then divide the entire equation by 3 to get y=4.

Next I plug y=4 into the equation, the new equation should be x+4=12. I then subtract 4 from both sides to get x=8.

The two numbers are :
x=8 y=4

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W sklepie spożywczym jest 11,73 kg cukierków czekoladowych. Pierwszy klient kupił 48 dag cukierków. Drugi klient kupił 4/5 pozos

Elenna [48]

Answer:

<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>

Step-by-step explanation:

The question is

<em> There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>

<em />

Givens

The total amount of chocolate candies is 11.73 kilograms.
First costumer bought 48 dag of candies. (1 kg equals 100 dags)
Second costumer bougth 4/5 of the remaining.
Another three costumers bought the same amount of candy.

Let's transform 48 dag to kilograms.

$48dag \times \frac{1kg}{100dag}= 0.48 \ kg$

Therefore, the first costumer bought 0.48 kilograms of candies.

The remaining amount is: $11.73kg-0.48kg=11.25kg$

Now, we need to multiply the remaining amount of candies with 4/5

$\frac{4}{5} \times 11.25kg=9 \ kg$

Therefore, the second costumer bought 9 kilograms of chocolate candies.

At last, we need to find the new remaining part of candies, which is

$11.25-9=2.25 \ kg$

Therefore, the last costumers got 2.25 kilograms of chocolate candies.

4 0

3 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago

What is the product of the binomals below (2x+3) (3x+3)

Korvikt [17]

Answer:

$3*(2x+3)*(x+1)$

Step-by-step explanation:

pull like terms from the problem to re-arrange it into a product

$\left(2x+3\right)\left(3x+3\right)\\3x + 3 = 3 \cdot (x + 1)\\3 \cdot (2x + 3) \cdot (x + 1)\\$

5 0

2 years ago

The length of a rectangle is given by the function l(x)=2x+1, and the width of the rectangle is given by the function w(x)=x+4.

Harlamova29_29 [7]

Answer:

a(x)=2x^2+9x+4

Step-by-step explanation:

We have been given the length and width, as well as the formula to find the area:

Length: 2x + 1

Width: x + 4

A = l * w

A = (2x + 1)(x + 4)

2x^2 + 8x + x + 4

We can add like terms now:

2x^2 + 9x + 4

Our area is 2x^2 + 9x + 4

Our answer would be a(x)=2x^2+9x+4

7 0

3 years ago

Read 2 more answers

What are the missing numbers help me

Aleksandr-060686 [28]

You are counting by 10s so the answer is 40,50,60,70,80
the complete sequence: 10,20,30,40,50,60,70,80,90,100

7 0

3 years ago

Read 2 more answers