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Jet001 [13]
3 years ago
5

A chemist has a 12.5 liter sample of neon gas at 1.00 atm and 30 c. If the chemist compresses the sample to 10.5 liters and hold

s the pressure constant, what is the new temperature of the neon gas?
Chemistry
1 answer:
ycow [4]3 years ago
8 0

Answer:

254.5 K

Explanation:

Data Given

initial volume V1 of neon gas = 12.5 L

final Volume V2 of neon gas = 10.5 L

initial Temperature T1 of neon gas = 30 °C

convert Temperature to Kelvin

T1 = °C +273

T1 = 30°C + 273 = 303 K

final Temperature T2 of neon gas = ?

Solution:

This problem will be solved by using Charles' law equation at constant pressure.

The formula used

                        V1 / T1 = V2 / T2

As we have to find out Temperature, so rearrange the above equation

                       T2 = V2 x T1 / V1

Put value from the data given

T2 = 10.5 L x 303 K / 12.5 L

T2 = 254.5K

So the final Temperature of neon gas = 254.5 K

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