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Anika [276]
3 years ago
7

Simple Chemistry Question - 5 points

Chemistry
2 answers:
ella [17]3 years ago
4 0
Boyle’s Law I’m pretty sure
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

Charles's Law

Explanation: Look at the attached file for information!!!

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El NaCI corresponde a un elemento?
Schach [20]

Answer:

Sodio (Na), elemento químico del grupo de los metales alcalinos (Grupo 1 [Ia]) de la tabla periódica. El sodio es un metal blanco plateado muy suave. El sodio es el metal alcalino más común y el sexto elemento más abundante en la Tierra, y comprende el 2,8 por ciento de la corteza terrestre.

Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

7 0
3 years ago
What do you look at to tell the reactivity of an atom?
tia_tia [17]

Answer:

The number of electrons in the outermost shell of an atom determines its reactivity. Noble gases have low reactivity because they have full electron shells. Halogens are highly reactive because they readily gain an electron to fill their outermost shell.

Explanation:

I hope this helped!

8 0
3 years ago
Which is not a form of potential energy?
san4es73 [151]
The answer is elastic.

Explanation: Energy comes in six basic forms: chemical, electrical, radiant, mechanical, thermal and nuclear. Therefore the answer is elastic because it is not one of the basic forms.

hope this helped!
7 0
3 years ago
Read 2 more answers
How does a sample of water at 38 °C compare to a sample of water at 295 K?
Sidana [21]

Converting the temperature, 295 K from Kelvin to Celsius scale:

295 K - 273 = 22^{0} C

Water has a boiling point of 100^{0}C and a melting point of 0^{0} C

When we compare water at two different temperatures, 22^{0}C and 38^{0}C we can say that water is in liquid form at both these temperatures as both of them are quite below the boiling temperature and above the melting temperature.

The temperature difference between water at the given two temperatures = 38^{0}C - 22^{0}C = 16^{0}C

Water at 38^{0}C is at a higher temperature and so is warmer than water at a lower temperature of 22^{0}C (or 295 K).


7 0
3 years ago
Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wa
zloy xaker [14]

Answer:

1.5×10⁷ Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength of radio wave (λ) = 20 m

Frequency (f) =?

Frequency and wavelength of a wave are related by the following equation:

v = λf

Where:

'v' is the velocity of electromagnetic wave.

'λ' is the wavelength

'f' is the frequency.

With the above formula, we can obtain the frequency of the radio wave as illustrated below:

Wavelength of radio wave (λ) = 20 m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 20 × f

Divide both side by 20

f = 3×10⁸ / 20

f = 1.5×10⁷ Hz

Thus the frequency of the radio wave is 1.5×10⁷ Hz

5 0
3 years ago
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