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noname [10]
3 years ago
9

How many significant figures are in 34 g

Chemistry
2 answers:
svetlana [45]3 years ago
7 0
2 significant figures

klemol [59]3 years ago
4 0
There r 2 significant figs
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The materials created from a chemical reaction are called
sweet [91]
The answer would be products
8 0
3 years ago
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One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 105 Pa undergoes a reversible adiabatic compressi
oksian1 [2.3K]

Answer:

  • final temperature (T2) = 748.66 K
  • ΔU = w = 5620.26 J
  • ΔH = 9367.047 J
  • q = 0

Explanation:

ideal gas:

  • PV = RTn

reversible adiabatic compression:

  • δU = δq + δw = CvδT

∴ q = 0

∴ w = - PδV

⇒ δU = δw

⇒ CvδT = - PδV

ideal gas:

⇒ PδV + VδP = RδT

⇒ PδV = RδT - VδP = - CvδT

⇒ RδT - RTn/PδP = - CvδT

⇒ (R + Cv,m)∫δT/T = R∫δP/P

⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303

∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5

⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212

⇒ T2/T1 = 2.512

∴ T1 = 298 K

⇒ T2 = (298 K)×(2.512)

⇒ T2 = 748.66 K

⇒ ΔU = Cv,mΔT

⇒ ΔU = (3/2)R(748.66 - 298)

∴ R = 8.314 J/K.mol

⇒ ΔU = 5620.26 J

⇒ w = 5620.26 J

  • H = U + nRT

⇒ ΔH = ΔU + nRΔT

⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)

⇒ ΔH = 5620.26 J + 3746.787 J

⇒ ΔH = 9367.047 J

8 0
3 years ago
The volume of the granite as
Trava [24]

The volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

<h3>How to calculate volume in cm³?</h3>

The conversion factor of mL and cm³ is given as follows: 1 mL = 1 cm³

According to this question, the volume of the granite as determined by water displacement is 9.35 mL.

This value in cm³ can be converted as follows:

9.35mL × 1 = 9.35cm³

Therefore, the volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

8 0
2 years ago
Cân bằng phương trình Mg+HCl-&gt;MgCl2+H2 bằng phương pháp thăng bằng
nignag [31]

quá trình oxi hóa: Mg0 -> Mg2+ + 2e-

quá trình khử: 2H+ + 2e- -> H2 (cần 2 H+ để tạo 1 H2)

----> chỉ cần thêm 2 vào trước HCl (vì H+ là do HCl cung cấp)

----> Mg + 2HCl -> MgCl2 + H2

yay :)

8 0
2 years ago
What is the temperature of 0.55 mol of gas at a pressure of 1.5 atm and a volume of 12.6 L ?
Taya2010 [7]

Answer:

The temperature is 419,1 K

Explanation:

We use the formula PV=nRT  T=PV/nR

T=1,5 atm x 12,6 L/0,55 mol x 0,082 l atm/K mol

T= 419,0687361 K

3 0
3 years ago
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