Answer:
use this formula it will help u .
Explanation:
If 60 ml of ethanol is diluted to a final volume of 400 ml, you create a 35 % ethanol solution.
First, realize that you creating a solution with that contains a polar solute (ethanol) with a polar solvent (water). Remember that "like dissolves like."
If you pour 60 ml of ethanol in a volumetric flask, you add 340 ml of water to dilute this solution to a final volume of 400 ml.
Volumetric flasks are designed to make or dilute solutions to specified final volume.
Since you have 60 ml of ethanol in a total solution of 400 ml, the percentage of ethanol is 35 %.
This result is obtained in the following manner.
ml/400. ml. = .35
.35 x 100% = 35 %
Amount of CH4 is excess, so no need to worry about it
<span>but the limiting factor is the Oxygen </span>
<span>according to stranded equation, </span>
<span>CH4 + 2 O2 --> CO2 + 2 H2O ΔH = -889 kJ/mol </span>
<span>just by taking proportions </span>
<span>(-889 kJ/mol) / 2 x 0.8 mol = - 355.6 kJ </span>
<span>so i think the answer is (a)</span>
The answer would be 5.60 x 10^3
Answer:
D) 65.7%
Explanation:
Based on the reaction:
2H2(g)+O2(g)⟶2H2O(l)
<em>2 moles of hydrogen produce 2 moles of water assuming an excess of oxygen.</em>
<em />
To find percent yield of the reaction we need to find theoretical yield (The yield assuming all hydrogen reacts producing water). With theoretical yield and actual yield (32.8g H₂O) we can determine percent yield as 100 times the ratio between actual yield and theoretical yield.
<em>Theoretical yield:</em>
Moles of 5.58g H₂:
5.58g H₂ ₓ (1 mol / 2.016g) = 2.768 moles H₂
As 2 moles of H₂ produce 2 moles of H₂O, if all hydrogen reacts will produce 2.768 moles H₂O. In grams:
2.768 moles H₂O ₓ (18.015g / mol) =
49.86g H₂O is theoretical yield
<em>Percent yield:</em>
Percent yield = Actual yield / Theoretical yield ₓ 100
32.8g H₂O / 49.86g ₓ 100 =
65.7% is percent yield of the reaction
<h3>D) 65.7%
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