Answer:
Shows the programming checking if num1 is greater than num2
Explanation:
So num1 and num2 are inputs
for you to code this you would need to put
num1=int(input("What is your first number? ))
and the same for num2 except change num1 for num 2 and first for second
When the input is completed, the computer will check if num 1 is greater than num2
it will do this by using a code something like:
if num1>num2:
Print("Your first input was greater than your second")
But in this example if it greater it just ends
But if it was less than you would put
if num1>num2:
Print("Your first input was greater than your second")
elif num1<num2:
Print("Your first input is less than your second")
So basically this code shows the computer checking if one number is greater than the other or not
Answer:
a. (210^6)((210^7)/(2.510^8)) = 1.610^5 bits or 160,000 bits
b. 1.6*10^5 bits or 160,000 bits
c. Bandwidth delay product of link is maximum number of bits that can be in the link
d. Width of bit = Length of link / bandwidth-delay product so 1 bit is 125 meters long. Yes, this is longer than a football field.
e. Width of bit = s/R
Hope this helps :)
Answer:
graficar una lista de entradas
graficar una lista de entradas
crear un nuevo objeto
condiciones de prueba
romper un ciclo
romper un ciclo
Explanation:
