When passing a list of parameters to a stored procedure by name, you can omit optional parameters by omitting the parameter name and value from the list.
<h3>What is optional parameter?</h3>
It should be noted that optional parameter simply means a method that doesn't force pass arguments at calling time.
In this case, when passing a list of parameters to a stored procedure by name, you can omit optional parameters by omitting the parameter name and value from the list.
Learn more about parameter on:
brainly.com/question/13151723
#SPJ12
<span>Cyclos is a project of STRO, a leading organisation on monetary innovations. Cyclos offers a complete on-line payment system with additional modules such as e-commerce and communication tools. [ [ The Cyclos platform permits institutions such as local banks and MFI`s to offer banking services that can stimulate local trade and development. Cyclos is also used by many organizations and</span>
Answer:
I'm pretty sure it's photogenic drawing.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
Ask google mam.............
