Evaluate the expression when a b 14 15 and b

$\begin{array}{cc}\text{Mathematical expression}&\text{Translation}\\ \\xy&\text{The product of two numbers}\\ \\\dfrac{x}{y}&x\text{ divided by }y\\ \\x-y&x\text{ minus }y\\ \\x+y&\text{the sum of }x\text{ and }y\\ \\y-x&x\text{ subtracted from }y\\ \\y:x&y\text{ divided by } x\\ \\x+y=6&\text{the sum of two numbers is 6}\\ \\xy=6&\text{the product of two numbers is 6}\\ \\6x=y&\text{6 times a number equals }y\\ \\y=x-6&\text{6 less than a number is }y\end{array}$

Step-by-step explanation:

$\begin{array}{cc}\text{Mathematical expression}&\text{Translation}\\ \\xy&\text{The product of two numbers}\\ \\\dfrac{x}{y}&x\text{ divided by }y\\ \\x-y&x\text{ minus }y\\ \\x+y&\text{the sum of }x\text{ and }y\\ \\y-x&x\text{ subtracted from }y\\ \\y:x&y\text{ divided by } x\\ \\x+y=6&\text{the sum of two numbers is 6}\\ \\xy=6&\text{the product of two numbers is 6}\\ \\6x=y&\text{6 times a number equals }y\\ \\y=x-6&\text{6 less than a number is }y\end{array}$

6 0

3 years ago

30 divided by 14 as a fraction

Anna71 [15]

Reduce the expression, if possible, by cancelling the common factors.

Exact form:
15/7
Decimal form:
2.142857 repeating
Mixed number form:
2 1/7

5 0

2 years ago

Solve 15 ≥ -3x or 2/3 x ≥ -2.

hjlf

Solve each of the equations independently, then determine if the are continuous or discontinuous.
15≥-3x [start here]
-5≤x [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5 [just turned around for analysis]

Next equation:
2/3x≥-2 [start here]
x≥-2(3/2) [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3

So, (according to the first equation) all values of x must be greater than, or equal to -5.

(According to the second equation) all values of x must be greater than, or equal to -3.
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.

4 0

3 years ago

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