| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
Any number that is divisible by 6 is already divisible by 2, but is not necessarily divisible by 12.
Counterexamples include: 6, 18, 30, 42, 54, and so on. You can find more by multiplying 6 by any odd number. However, multiplying 6 by an even number provides another "2" that would make it divisible by 12.
Answer:
X = 34
Step-by-step explanation:
Respuesta:
Kansas, Misuri = 8
Paradise, Michigan = 3
Explicación paso a paso:
El rango intercuartílico (IQR) = Q3 - Q1
Q3 = 3/4 (n + 1) th término
n = número de muestras
Q1 = 1/4 (n + 1) th término
Kansas Misuri:
23,25,28,28,32,33,35
Datos pedidos: 23, 25, 28, 28, 32, 33, 35
n = 7
Q1 = 1/4 * 8 = 2do trimestre = 25
Q3 = 3/4 * 8 = 6. ° tem = 33
Q1 = 33 - 25 = 8
Paradise, Michigan:
16,24,26,26,26,27,28
Datos pedidos: 16,24,26,26,26,27,28
Q1 = 1/4 * 8 = 2do = 24
Q3 =. 3/4 * 8 = 6to = 27
Q3 - Q1 = 27 - 24 = 3
