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elixir [45]
3 years ago
5

Need help solving problem number 41

Mathematics
1 answer:
Pani-rosa [81]3 years ago
3 0
Ok rmemeber
√(a/b)=(√a)/(√b)
and
√ab=(√a)(√b)
and
(a^m)/(a^n)=a^(m-n)
so

ignore 11 for now, we will get to that at end

\sqrt{ \frac{49a^{5}}{4a^{3}}}=
\frac{\sqrt{49a^{5})}{\sqrt{4a^{3}}}=
\frac{(\sqrt{49})(\sqrt{a^{5}})}{(\sqrt{4)(\sqrt{a^{3}}}=
\frac{(7)(a^{2} \sqrt{a}) }{(2)(a \sqrt{a}) }=
\frac{7a^{2} \sqrt{a} }{2a \sqrt{a} }=
\frac{7a}{2}
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