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cluponka [151]
3 years ago
15

n a newspaper, it was reported that yearly robberies in Springfield were down 20% to 176 in 2011 from 2010. How many robberies w

ere there in Springfield in 2010?
Mathematics
2 answers:
Ede4ka [16]3 years ago
3 0

Answer: There were 220 robberies in Springfield in 2010

Step-by-step explanation: If the robberies were reported to be down 20% and the new figure is 176, it simply means the figure 176 depicts 80% (or 0.8) of the figure from year 2010.

We shall take the figure in year 2010 as x, which is 100% (or 1.0) and year 2011 is 176 which is 80% (or 0.8). What we now have is;

176/x = 0.8

176/x = 4/5

By cross multiplication we now have;

(176 x 5)/4 = x

880/4 = x

220 = x

Therefore, there were 220 robberies in Springfield in 2010

Masja [62]3 years ago
3 0

Answer: There were 220 robberies in Springfield in 2010.

Step-by-step explanation:

Hi, to answer this question we have to write an equation with the information given.

Since the robberies decreased 20%, it means that 2011 are robberies are the 80% (100%-20%) of the 2010 robberies (x).

So if we multiply the yearly robberies in 2010 (x) by 0.8 (decimal form, 80/100=0.8) , we obtain the number of yearly robberies in 2011 (176).

x (0.80) = 176

Solving for x

x = 176/0.8

x = 220  robberies (2010)

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2 years ago
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Answer:

Carl's hourly pay rate is $16

Step-by-step explanation:

Let x is the hourly rate of Carl and y is the hourly rate of Derrick

∵ Carl's hourly rate is $x

∵ Derrick's hourly rate is $y

∵ Carl worked for 15 hours and Derrick worked for 20 hours

∴ Their combined pay was 15x + 20y

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∴ 15x + 20y = 640 ⇒ (1)

∵ The next week, Carl worked 20 hours and Derrick worked 25 hours

∴ Their combined pay was 20x + 25 y

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→ Equate the value of the combined pay

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Now we have a system of equations to solve it

→ Multiply equation (1) by 5 and equation (2) by -4

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→ Add equations (3) and (4)

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∴ x = 16

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See attachment for steps

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Hope this helps!

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Answer:

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