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pogonyaev
3 years ago
12

Drag a statement or reason into the blank to complete this proof;

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0
\left[x \right] = \left[ 5\right][x]=[5]2(x+1)/−2 = 8−2 _________
_________ Simplifying

\left[x \right] = \left[ 2\right][x]=[2] = x + 1 + -4
x = -5
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2) Solving an equation - using the distributive property and inverse operations to solve 4/5
ella [17]
What is there to solve
6 0
3 years ago
What type of transformation is y=(x-2)^3+5
leva [86]
The negative 2 tells us that the graph has a horizontal shift of 2 units to the right and the plus 5 tells us that the graph has a vertical shift up by 5 units.
5 0
2 years ago
How would I find the value of X??
Ronch [10]
The two angles are corresponding angles, which means they are equal to each other. Make them equal to each other in an equation.

11x - 2 = 130
Add 2 to both sides.

11x = 132
Divide both sides by 11.

x = 12
4 0
3 years ago
Read 2 more answers
1) Solve the system by elimination?
lesya692 [45]

Answer:

1) (-6,-9)

times the top equation buy -4 so you cancel out the y

so it be -8x+4y=12 no cancel out the y's

so it be -8x=12 and 5x=6

now combined like terms to get -3x= 36

x = -6 now go plug that back in one of the equations to get y

y = -9

2) (-2,-5)

now on this one you going to substitute y= (2x-1) for y in the otheir eqaution

so it look like 3x-(2x-1)=-1

do your combining of like terms and your division & you get x = -2

now plug x in to y=2x-1 to get y = -5

6 0
3 years ago
What is the area, in square units, of trapezoid ABCD shown below?
SOVA2 [1]

Given:

Trapezoid with bases 10 and 20, and height of the trapezoid is 6.

To find:

The area of the trapezoid.

Solution:

We know that the area of a trapezoid is:

A=\dfrac{1}{2}h(b_1+b_2)

Where, h is the height of the trapezoid and b_1,b_2 are bases of the trapezoid.

Putting h=6, b_1=10,b_2=20 in the above formula, we get

A=\dfrac{1}{2}(6)(10+20)

A=3(30)

A=90

The area of the trapezoid is 90 sq units. Therefore, the correct option is A.

7 0
2 years ago
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