Answer:
Step-by-step explanation:
I assume that you mean
sec(x)-tan(x) = 1 / ( sec(x) + tan(x) ) , right ?
then this is equivalent to
[ sec(x) - tan(x) ] x [ sec(x) + tan(x) ] = 1
let s evaluate it, we got
sec2(x) - sec(x)tan(x) + - sec(x)tan(x) - tan2(x) = sec2(x) - tan2(x)
= (1 - sin2(x) ) / cos2(x) = cos2(x) / cos2(x) = 1
as cos2(x) + sin2(x) = 1
A) If you have 12 dogs and cats (I assume 12 in total) and divide those by two, you get six dogs and six cats. It has to be more dogs than cats, and the sum of those two has to be twelve. So to reach the sum 12, while one number is bigger that the other, the number has to be 7 or more.
Area is found by taking the length time width or A=lw
240=L x 15 divide both sides by 15
Length = 16 meters
Given problem is -4.2y+2.1>-2.52.
To solve this, we combine numbers by transposing -2.52 to the left side and transposing variable term in the right side as shown below:
2.1+2.52>4.2y
Perform addition of values 2.1 and 2.52,
4.62>4.2y
Then, divide both sides with 4.2 and the result is 1.1>y.
The answer is y<1.1.
